如何计算文件中的字符并按字母数字顺序打印 [英] How to count characters in a file and print them sorted alphanumerically

问题描述

(如果标题更好，请进行编辑，我无法正确解释！:) 这是我的代码:

(If you have a better title, do edit, I couldn't explain it properly! :) So this is my code:

with open('cipher.txt') as f:
    f = f.read().replace(' ', '')

new = []
let = []
for i in f:
    let.append(i)
    if i.count(i) > 1:
        i.count(i) == 1
    else:
        new = sorted([i + ' ' + str(f.count(i)) for i in f])
for o in new:
  print(o)

这是cipher.txt:

xli uymgo fvsar jsb

我应该打印出使用的字母以及使用了多少次，我的代码可以正常工作，但是我需要按字母顺序打印，我尝试将它们放入列表list(a)中，然后对它们进行排序，但是我没有不太明白，有什么想法吗?预先感谢！

I'm supposed to print out the letters used and how many times they are used, my code works, but I need it alphabetical, I tried putting them in a list list(a) and then sorting them, but i didn't quite get it, any ideas? Thanks in advance!

推荐答案

每当处理计数时，都可以使用 collections.Counter 此处:

Whenever dealing with counting, you can use collections.Counter here:

>>> from collections import Counter
>>> print sorted(Counter('xli uymgo fvsar jsb'.replace(' ', '')).most_common())
[('a', 1), ('b', 1), ('f', 1), ('g', 1), ('i', 1), ('j', 1), ('l', 1), ('m', 1), ('o', 1), ('r', 1), ('s', 2), ('u', 1), ('v', 1), ('x', 1), ('y', 1)]

---

如果您无法导入任何模块，则可以将a附加到列表中，然后对其进行排序:

---

If you can't import any modules, then you can append a to a list and then sort it:

new = []
for i in f:
    new.append(i + ' ' + str(f.count(i)) # Note that i is a string, so str() is unnecessary

或者，使用列表推导:

new = [i + ' ' + str(f.count(i)) for i in f]

最后，要进行排序，只需将sorted()放在其周围.不需要额外的参数，因为您的结果是按字母顺序排列的:).

Finally, to sort it, just put sorted() around it. No extra parameters are needed because your outcome is alphabetical :).

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