以自然降序对目录文件名数组进行排序 [英] Sorting an array of directory filenames in descending natural order

问题描述

我有一个内容目录，以自然降序返回.

I have a content directory to be returned in descending natural order.

我正在使用scandir()和natsort()，但是添加array_reverse()不会产生任何结果.

I'm using scandir() and natsort(), but the addition of array_reverse() yields no results.

我一直在研究使用opendir()和readdir()的组合以及其他会影响此结果的东西.

I've been researching using a combination of opendir() and readdir() as well what ever else to affect this outcome.

要排序的项目是编号的图像文件.它们将返回为:10 9 8 7依此类推，但类似1000 999 998 997 ...直到0

The items to be sorted are numbered image files. They are to be returned as: 10 9 8 7 and so on, but like from like 1000 999 998 997 ... until 0

这是我当前的代码:

$dir = 'dead_dir/dead_content/';
$launcher = scandir($dir);
natsort($launcher);
array_reverse($launcher, false);
foreach ($launcher as $value) {
    if (in_array(pathinfo($value, PATHINFO_EXTENSION), array('png'))) {
        echo '<img src="dead_dir/dead_content/'.$value.'" />'
    }
}

推荐答案

 $dir='dead_dir/dead_content/';
 $launcher= scandir($dir);
 natsort($launcher);
 $r_launcher = array_reverse($launcher,true);

 foreach($r_launcher as $value ){
   if(in_array(pathinfo($value, PATHINFO_EXTENSION),array('png'))){
       echo '<img src="dead_dir/dead_content/'.$value.'" />'}}

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