合并两个具有不同键但值相同的无序对象? [英] Merge two unordered objects with different keys but same value?
本文介绍了合并两个具有不同键但值相同的无序对象?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
合并obj1和obj2之类的对象以在javascript中获取obj3.
Merge objects like obj1 and obj2 to get obj3 in javascript.
obj1 = [{fruit: 'watermelon', sweetness: 3},{fruit: 'banana', sweetness: 4},{fruit: 'apple', sweetness: 5}]
obj2 = [{fruit_name: 'apple', color: 'red'},{fruit_name: 'banana', color:'yellow'},{fruit_name: 'watermelon', color:'green'}]
obj3 = [{fruit_name: 'apple', color: 'red', sweetness: 5},{fruit_name: 'banana', color:'yellow', sweetness: 4},{fruit_name: 'watermelon', color:'green', sweetness: 3}]
推荐答案
您可以先先通过使用 #map()
>功能-参见下面的演示:
You can first create a hashtable
by merging similar objects using #forEach
and then extract the required array using a #map()
function - see demo below:
var obj1 = [{fruit: 'watermelon', sweetness: 3},{fruit: 'banana', sweetness: 4},{fruit: 'apple', sweetness: 5}],
obj2 = [{fruit_name: 'apple', color: 'red'},{fruit_name: 'banana', color:'yellow'},{fruit_name: 'watermelon', color:'green'}], hash = {};
// function to create a hashtable
function classify(e) {
if(hash[e.fruit] || hash[e.fruit_name]) {
Object.keys(e).forEach(function(c){
hash[e.fruit || e.fruit_name][c] = e[c];
});
} else {
hash[e.fruit_name || e.fruit] = e;
}
}
// add to hash
obj1.forEach(classify);
obj2.forEach(classify);
// extract the result
var obj3 = Object.keys(hash).map(function(e){
delete hash[e]['fruit'];
return hash[e];
});
console.log(obj3);
.as-console-wrapper{top:0;max-height:100%!important;}
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