Spring Boot中的TransientPropertyValueException [英] TransientPropertyValueException in Spring Boot

问题描述

我有LoginCredential课:

@Data
@Entity
public class LoginCredential implements Serializable {
   @Id
   @GeneratedValue(strategy = GenerationType.AUTO)
   Long userID;
   String eMail;
   String passwordHash;
   @GeneratedValue(strategy = GenerationType.AUTO)
   @OneToOne(mappedBy = "loginCredential", fetch = FetchType.LAZY)
   User user;
}

这是我的User课:

@Data
@Entity
public class User {
   @Id
   @GeneratedValue(strategy = GenerationType.AUTO)
   Long userID;
   @OneToOne(fetch = FetchType.LAZY,targetEntity = LoginCredential.class)
   @JoinColumn(name = "userID",referencedColumnName = "userID")
   private LoginCredential loginCredential;
}

而我的LoginCredentialController的 POST -ing方法很简单:

And my LoginCredentialController's POST-ing method is simple :

@PostMapping("/login")
LoginCredential newLoginCredential(@RequestBody LoginCredential newLoginCredential) {
    logger.debug(newLoginCredential);
    LoginCredential a=repository.save(newLoginCredential);
    logger.debug(a);
    return a;
}

现在，当我尝试此命令时:curl -X POST -H "Content-Type: application/json" -d "{ \"email\": \"1\"}" http://localhost:8080/login

Now when I tried this command : curl -X POST -H "Content-Type: application/json" -d "{ \"email\": \"1\"}" http://localhost:8080/login

我得到的LoginCredential没有任何错误，要提到的user字段是null.

I get a LoginCredential without any error, to be mentioned user field is null.

这就是为什么我尝试此命令curl -X POST -H "Content-Type: application/json" -d "{ \"email\": \"1\",\"user\":{} }" http://localhost:8080/login

That's why I tried this command curl -X POST -H "Content-Type: application/json" -d "{ \"email\": \"1\",\"user\":{} }" http://localhost:8080/login

哪个让我出错:

{
  "status" : 500,
  "error" : "Internal Server Error",
  "message" : "org.hibernate.TransientPropertyValueException: object references an unsaved transient instance - save the transient instance before flushing : com.mua.cse616.Model.LoginCredential.user -> com.mua.cse616.Model.User; org.hibernate.TransientPropertyValueException: object references an unsaved transient instance - save the transient instance before flushing : com.mua.cse616.Model.LoginCredential.user -> com.mua.cse616.Model.User",
  "trace":....
}

Application.properties

pom.xml

推荐答案

您遇到三个问题

1. 缺少cascade选项可从LoginCredential保存触发User实体创建.
2. User上缺少@MapsId注释，因此它们共享相同的id，否则LoginCredential及其创建的User将具有不同的id值，因为它们在@Id列上均具有@GeneratedValue(strategy = GenerationType.AUTO)
3. 未设置双方关系...

1. Lacking a cascade option to trigger User entity creation from LoginCredential save.
2. Lacking @MapsId annotation on User so that they share the same id, otherwise LoginCredential and its created User will have different id values for both of them has @GeneratedValue(strategy = GenerationType.AUTO) on their @Id columns
3. Not setting both sides of the relationship...

要解决所有将实体更改为下面的问题(我还删除了一些无用的注释和值)；

To fix all you need to change your entities to below (I also removed some useless annotations and values);

@Data
@Entity
public class User {

    @Id
    Long userID;

    @JsonBackReference
    @MapsId
    @OneToOne(fetch = FetchType.LAZY)
    @JoinColumn(name = "userID", referencedColumnName = "userID")
    @ToString.Exclude
    private LoginCredential loginCredential;
}

和

@Data
@Entity
public class LoginCredential {

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    Long userID;
    String eMail;
    String passwordHash;

    @JsonManagedReference
    @OneToOne(mappedBy = "loginCredential", fetch = FetchType.LAZY, cascade = CascadeType.PERSIST)
    private User user;
}

在最终确定端点之前，还需要设置关系的两面；

Also need to set both sides of the relationship before finalizing your endpoint;

Optional.ofNullable(loginCredential.getUser())
        .ifPresent(user -> user.setLoginCredential(loginCredential));
loginCredentialRepo.save(loginCredential);

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