在Spring WebSockets中发送错误消息 [英] Sending Error message in Spring websockets

问题描述

我正在尝试通过SockJS在带有STOMP的Spring Websocket中发送错误消息.

I am trying to send error messages in Spring websockets with STOMP over SockJS.

我基本上是在尝试实现

I am basically trying to achieve which is being done here.

这是我的异常处理程序

@MessageExceptionHandler
@SendToUser(value = "/queue/error",broadcast = false)
public ApplicationError handleException(Exception message) throws ApplicationError {
        return  new ApplicationError("test");
}

我正在订阅

stompClient.subscribe('/user/queue/error', stompErrorCallback, {token: accessToken});

在我的情况下，用户未通过身份验证，但来自

User in my case is not authenticated, but from here

虽然用户目的地通常暗指经过身份验证的用户，但它 并非严格要求.未关联的WebSocket会话 经过身份验证的用户可以订阅用户目的地.在 在这种情况下，@ SendToUser批注的行为与 使用broadcast = false，即仅定位发送该会话的会话 邮件正在处理.

While user destinations generally imply an authenticated user, it isn’t required strictly. A WebSocket session that is not associated with an authenticated user can subscribe to a user destination. In such cases the @SendToUser annotation will behave exactly the same as with broadcast=false, i.e. targeting only the session that sent the message being handled.

当我从myHandler抛出此错误时，所有这些工作正常，是我在websocket配置中定义的Websocket处理程序.

All this works fine when I am throwing this error from myHandler which is my Websocket Handler defined in websocket config.

我有一个ClientInboundChannelInterceptor扩展了ChannelInterceptorAdapter，它拦截了preSend中的所有消息.

I have a ClientInboundChannelInterceptor which extends ChannelInterceptorAdapter which intercepts all the messages in preSend.

如果此拦截器有任何异常，我想将其扔回发送此消息的用户会话中，

In case of any exception in this interceptor, I want to throw it back to the user session which sent this message,

public class ClientInboundChannelInterceptor extends ChannelInterceptorAdapter {
    @Autowired
    @Lazy(value = true)
    @Qualifier("brokerMessagingTemplate")
    private SimpMessagingTemplate simpMessagingTemplate;

    @Override
    public Message<?> preSend(Message message, MessageChannel channel) throws IllegalArgumentException{
         if(some thing goes wrong)
           throw new RuntimeException();
    }

    @MessageExceptionHandler
    @SendToUser(value = "/queue/error",broadcast = false)
    public ApplicationError handleException(RuntimeException message) throws    ApplicationError {
        return  new ApplicationError("test");
    }
}

@MessageExceptionHandler不会捕获此异常.因此，我尝试使用simpMessagingTemplate直接将其发送给用户.

@MessageExceptionHandler does not catch this exception. So I tried sending it to the user directly using simpMessagingTemplate.

我基本上想做:

simpMessagingTemplate.convertAndSendToUser(SOMETHING,"/queue/error",e);

某些内容应该是正确的用户名，但在我的情况下用户未通过身份验证，因此我不能使用headerAccessor.getUser().getName()

SOMETHING should be the correct username but user is not authenticated in my case, so I can't use headerAccessor.getUser().getName()

我什至尝试过

simpMessagingTemplate.convertAndSendToUser(headerAccessor.getHeader("","/queue/error",e, Collections.singletonMap(SimpMessageHeaderAccessor.SESSION_ID_HEADER, headerAccessor.getSessionId()));

但这不起作用.

我什至尝试用headerAccessor.getSessionId()代替用户名，但这似乎不起作用.

I have even tried headerAccessor.getSessionId() in the place of username, but that does not seem to work.

正确的方法是什么?

我应该在convertAndSendToUser中使用什么作为用户名?

What should I use as username in convertAndSendToUser?

推荐答案

我的最初直觉是正确的，在未经身份验证的用户情况下，使用sessionId作为用户名，但是问题出在头文件上.

My initial intuition was correct, sessionId is used as the username in case of unauthenticated user situations, but the problem was with headers.

在通过@SendToUser和simpMessagingTemplate.convertAndSendToUser()进行了几个小时的调试之后，我意识到如果使用@SendToUser标头，则会自动设置标头，如果使用simpMessagingTemplate.convertAndSendToUser()，则必须显式定义标头.

After few hours of debugging through @SendToUser and simpMessagingTemplate.convertAndSendToUser(), I realised that if we use @SendToUser headers will be set automatically and we have to explicitly define the headers if we are using simpMessagingTemplate.convertAndSendToUser().

@SendToUser正在设置两个标题，

simpMessageType:SimpMessageType.MESSAGE，simpSessionId:sessionId

simpMessageType:SimpMessageType.MESSAGE,simpSessionId:sessionId

所以我尝试添加标题，

String sessionId = headerAccessor.getSessionId();
Map<String,Object> headerMap = new HashMap<>();
headerMap.put("simpMessageType", SimpMessageType.MESSAGE);
headerMap.put("simpSessionId",sessionId);   
simpMessagingTemplate.convertAndSendToUser(headerAccessor.getSessionId(),"/queue/error",e,headerMap);

它不起作用，我尝试将标题设为MessageHeaders

It did not work, I have tried giving the headers as MessageHeaders

String sessionId = headerAccessor.getSessionId();
Map<String,Object> headerMap = new HashMap<>();
headerMap.put("simpMessageType", SimpMessageType.MESSAGE);
headerMap.put("simpSessionId",sessionId); 
MessageHeaders headers = new MessageHeaders(headerMap);

simpMessagingTemplate.convertAndSendToUser(headerAccessor.getSessionId(),"/queue/error",e,headers);

也不起作用.

经过更多调试之后，我发现了设置标头的正确方法，可能这是创建这些标头的唯一方法(来自SendToMethodReturnValueHandler.java).

After some more debugging I found out the correct way to set the headers, and probably this is the only way to create these headers(from SendToMethodReturnValueHandler.java).

private MessageHeaders createHeaders(String sessionId) {
    SimpMessageHeaderAccessor headerAccessor = SimpMessageHeaderAccessor.create(SimpMessageType.MESSAGE);
    headerAccessor.setSessionId(sessionId);
    headerAccessor.setLeaveMutable(true);
    return headerAccessor.getMessageHeaders();
}

最后，

String sessionId = headerAccessor.getSessionId();
template.convertAndSendToUser(sessionId,"/queue/error","tesssssts",createHeaders(sessionId));

成功了！

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