spring-mvc:如何以"a/b/{c}"形式映射URI模板? [英] spring-mvc: how to map URI templates in the form of "a/b/{c}"?

问题描述

我可以使用"/a/b"或"/a/{b}"形式的URI模板.但是，当我尝试"/a/b/{c}"时，我在日志中收到了一条HTTP 404和一条消息，消息形式为未找到带有URI [/myapp/a/b/c]的HTTP请求的映射. ..但是我也在日志中看到了这些消息，这使我相信映射是正确的...?

I can get a URI template in the form of "/a/b" or "/a/{b}" to work. But when I try "/a/b/{c}", I get a HTTP 404 and a message in the log in the form of "No mapping found for HTTP request with URI [/myapp/a/b/c]..." But I see these message in the log also which leads me to believe that the mappings are correct...?

INFO: Mapped URL path [/a] onto handler 'AController'
Nov 16, 2010 12:18:39 PM org.springframework.web.servlet.handler.AbstractUrlHandlerMapping registerHandler
INFO: Mapped URL path [/a/*] onto handler 'AController'
Nov 16, 2010 12:18:39 PM org.springframework.web.servlet.handler.AbstractUrlHandlerMapping registerHandler

我注意到所有 spring-mvc文档中的示例以"/a/{b}"或/a/{b}/c/{d}"的形式显示了URI模板. "/a/b/{c}"是不可能的吗?我是否需要在web.xml中进行配置以使这种情况发生?或者某些(错误)配置会阻止该模式被映射?目前我的调度程序servlet已映射到:

I noticed all the examples in the spring-mvc docs show URI templates in the form of "/a/{b}" or /a/{b}/c/{d}". So is "/a/b/{c}" not possible? Is there anything I need to configure in web.xml to make this happen? Or can some (mis)configuration prevent that pattern from being mapped? Currently my dispatcher servlet is mapped to:

<url-pattern>/</url-pattern>

控制器看起来像这样:

@Controller
public class AController {
    @RequestMapping(value = "/a/b/{c}", method = RequestMethod.GET)
    public ModelAndView show() {
        ModelAndView modelAndView = new ModelAndView("A");
        return modelAndView;
    }
}

访问 http://localhost:8080/myapp/a/b/c 返回404，我在日志中看到了这一点:

Accessing http://localhost:8080/myapp/a/b/c returns a 404 and I see this in the log:

Nov 16, 2010 12:19:06 PM org.springframework.web.servlet.DispatcherServlet noHandlerFound
WARNING: No mapping found for HTTP request with URI [/myapp/a/b/c] in DispatcherServlet with name 'dispatcher'

关于如何获取URI模式以正确映射的任何想法吗?

Any ideas on how I get my URI pattern to get mapped correctly?

推荐答案

仅当ControllerClassNameHandlerMapping用作处理程序映射时，才会出现这种情况.

It looks like this happens only when ControllerClassNameHandlerMapping is used as a handler mapping.

带注释的控制器通常与DefaultAnnotationHandlerMapping一起使用，在这种情况下，一切正常.

Annotated controllers are usually used with DefaultAnnotationHandlerMapping, and in that case everything works fine.

实际上，它看起来像ControllerClassNameHandlerMapping的合法行为.它将aController映射到/a/*而不是/a/**，因此仅接受一级路径层次结构.同样，如果您需要完全的灵活性，请使用DefaultAnnotationHandlerMapping.

Actually, it looks like a legitimate behaviour of ControllerClassNameHandlerMapping. It maps aController to /a/* rather than /a/**, therefore only one level of path hierarchy is accepted. And again, if you need full flexibility, use DefaultAnnotationHandlerMapping.

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