带有未经身份验证的用户的Spring Stomp @SendToUser无法正常工作 [英] Spring Stomp @SendToUser with unauthenticated user not working

问题描述

我正尝试使用@SendToUser响应未经身份验证的用户.

I'm trying to respond to an unauthenticated user using @SendToUser.

• 春季4.1.1

我正在使用一个新创建的Spring Boot应用程序，我唯一的配置是:

I'm using a newly created Spring Boot application and the only config I have is:

@Configuration
@EnableWebSocketMessageBroker
public class WebSocketConfig extends AbstractWebSocketMessageBrokerConfigurer {
    @Override
    public void registerStompEndpoints(StompEndpointRegistry registry) {
        registry.addEndpoint("/stomp").withSockJS();
    }
    @Override
    public void configureMessageBroker(MessageBrokerRegistry registry) {
        registry.enableSimpleBroker("/topic");
        registry.setApplicationDestinationPrefixes("/app");
        registry.setUserDestinationPrefix("/user"); 
    }
}

控制器代码:

@MessageMapping("/search")
@SendToUser("/search")
public String search(@Payload String xxx) {
    return "TEST1234";
}

---

JS:

---

JS:

var socket = new SockJS('/webapp/stomp');
stompClient = Stomp.over(socket);
stompClient.connect({}, function(frame) {
    stompClient.subscribe('/user/search', function(data){
        alert(data.body);
    });
});

Spring输出:

DEBUG  org.springframework.web.servlet.DispatcherServlet: 996 - Successfully completed request
DEBUG   o.s.w.s.handler.LoggingWebSocketHandlerDecorator:  45 - New WebSocketServerSockJsSession[id=shizav88]
DEBUG       o.s.m.simp.broker.SimpleBrokerMessageHandler: 158 - Processing CONNECT session=shizav88
DEBUG      o.s.m.simp.user.UserDestinationMessageHandler: 187 - Translated /user/search -> [/search-usershizav88]

JS:

var name = document.getElementById('name').value;
stompClient.send("/app/search", {}, "test"));

Spring输出:

DEBUG     o.s.m.s.a.s.SimpAnnotationMethodMessageHandler: 348 - Searching methods to handle SEND /app/search session=shizav88
DEBUG     o.s.m.s.a.s.SimpAnnotationMethodMessageHandler: 446 - Invoking de.benneq.next.search.SearchController#search[1 args]
DEBUG   o.s.b.factory.support.DefaultListableBeanFactory: 247 - Returning cached instance of singleton bean 'searchController'
DEBUG      o.s.m.simp.user.UserDestinationMessageHandler: 187 - Translated /user/shizav88/search -> [/search-usershizav88]

---

在我看来，Spring会将订阅映射到/search-usershizav88.然后使用/search-usershizav88发送响应.但是我的JS客户端什么也没收到.

---

To me it looks like Spring maps the subscription to /search-usershizav88. And then uses /search-usershizav88 to send the response. But my JS client does not receive anything.

出什么问题了?

推荐答案

现在我可以使用它了，但是我真的不知道为什么为什么:

Now I got it working, but I don't really know WHY:

@Configuration
@EnableWebSocketMessageBroker
public class WebSocketConfig extends AbstractWebSocketMessageBrokerConfigurer {
    @Override
    public void registerStompEndpoints(StompEndpointRegistry registry) {
        registry.addEndpoint("/stomp").withSockJS();
    }
    @Override
    public void configureMessageBroker(MessageBrokerRegistry registry) {
        registry.enableSimpleBroker("/queue", "/topic"); // <- added "/queue"
        registry.setApplicationDestinationPrefixes("/app");
        registry.setUserDestinationPrefix("/user"); 
    }
}

控制器:

@MessageMapping("/search")
@SendToUser // <- maps to "/user/queue/search"
public String search(@Payload String xxx) {
    return "TEST1234";
}

JS:

stompClient.subscribe('/user/queue/search', function(data){
    alert(data.body);
});

Spring输出:

DEBUG  org.springframework.web.servlet.DispatcherServlet: 996 - Successfully completed request
DEBUG   o.s.w.s.handler.LoggingWebSocketHandlerDecorator:  45 - New WebSocketServerSockJsSession[id=fkbmnpkj]
DEBUG       o.s.m.simp.broker.SimpleBrokerMessageHandler: 158 - Processing CONNECT session=fkbmnpkj
DEBUG      o.s.m.simp.user.UserDestinationMessageHandler: 187 - Translated /user/queue/search -> [/queue/search-userfkbmnpkj]
DEBUG       o.s.m.simp.broker.SimpleBrokerMessageHandler: 175 - Processing SUBSCRIBE /queue/search-userfkbmnpkj id=sub-0 session=fkbmnpkj

现在日志中还有一行，它表示正在正在处理SUBSCRIBE/queue/search-userfkbmnpkj id = sub-0 session = fkbmnpkj

Now there's an additional line in the log, which says that it is Processing SUBSCRIBE /queue/search-userfkbmnpkj id=sub-0 session=fkbmnpkj

以前没有.

如果有人可以解释为什么我需要/queue映射才能使其正常工作，那仍然会很好.

It would still be nice, if someone could explain why I need the /queue mapping for this to work properly.

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