在##串联之前评估预处理器令牌 [英] Evaluate preprocessor token before ## concatenation
问题描述
我想先评估一个令牌,然后再将其与其他对象连接. 问题"是该标准将行为指定为
I would like to evaluate a token before it is concatenated with something else. The "problem" is that the standard specifies the behaviour as
在重新检查替换列表之前,需要更多的宏名称 替换,替换中##预处理令牌的每个实例 列表(不是从参数中删除)并进行前面的预处理 令牌与以下预处理令牌串联.
before the replacement list is reexamined for more macro names to replace, each instance of a ## preprocessing token in the replacement list (not from an argument) is deleted and the preceding preprocessing token is concatenated with the following preprocessing token.
因此在以下示例中,
#include <stdlib.h>
struct xy {
int x;
int y;
};
struct something {
char * s;
void *ptr;
int size;
struct xy *xys;
};
#define ARRAY_SIZE(a) ( sizeof(a) / sizeof((a)[0]) )
#define DECLARE_XY_BEGIN(prefix) \
struct xy prefix ## _xy_table[] = {
#define XY(x, y) {x, y},
#define DECLARE_XY_END(prefix) \
{0, 0} \
}; \
struct something prefix ## _something = { \
"", NULL, \
ARRAY_SIZE(prefix ## _xy_table), \
&(prefix ## _xy_table)[0], \
};
DECLARE_XY_BEGIN(linear1)
XY(0, 0)
XY(1, 1)
XY(2, 2)
XY(3, 3)
DECLARE_XY_END(linear1)
#define DECLARE_XY_BEGIN_V2() \
struct xy MYPREFIX ## _xy_table[] = {
#define DECLARE_XY_END_V2() \
{0, 0} \
}; \
struct something MYPREFIX ## _something = { \
"", NULL, \
ARRAY_SIZE(MYPREFIX ## _xy_table), \
&(MYPREFIX ## _xy_table)[0], \
};
#define MYPREFIX linear2
DECLARE_XY_BEGIN_V2()
XY(0, 0)
XY(2, 1)
XY(4, 2)
XY(6, 3)
DECLARE_XY_END_V2()
#undef MYPREFIX
最后一个声明扩展为
struct xy MYPREFIX_xy_table[] = {
{0, 0},
{2, 1},
{4, 2},
{6, 3},
{0, 0} }; struct something MYPREFIX_something = { "", 0, ( sizeof(MYPREFIX_xy_table) / sizeof((MYPREFIX_xy_table)[0]) ), &(MYPREFIX_xy_table)[0], };
不是
struct xy linear2_xy_table[] = {
{0, 0},
{2, 1},
{4, 2},
{6, 3},
{0, 0} }; struct something linear2_something = { "", 0, ( sizeof(linear2_xy_table) / sizeof((linear2_xy_table)[0]) ), &(linear2_xy_table)[0], };
就像我想要的那样.有什么方法可以定义产生此结果的宏吗?第一组宏可以,但是我想避免前缀重复,并且只定义一次.那么可以用#define
设置前缀并让宏使用它吗?
like I want to. Is there some way of defining macros that produces this? The first set of macros does, but I would like to avoid the prefix duplication and only have this defined once. So is it possible to set the prefix with #define
and let the macros use that?
推荐答案
您可以为此使用二级扩展.
You can use second level expansion for this, eg.
#define XY_HLP1(a) DECLARE_XY_BEGIN(a)
#define XY_HLP2(a) DECLARE_XY_END(a)
#define DECLARE_XY_BEGIN_V2() XY_HLP1(MYPREFIX)
#define DECLARE_XY_END_V2() XY_HLP2(MYPREFIX)
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