闭包参数列表的上下文类型需要1个参数，但指定了4个 [英] Contextual type for closure argument list expects 1 argument, but 4 were specified

问题描述

我已升级到Xcode 7，并且正在使用Alamofire来管理API调用，但出现此错误:

I upgraded to Xcode 7 and I am using Alamofire to manage API calls and I am getting this error:

闭包参数列表的上下文类型需要1个参数，但指定了4个参数"

'Contextual type for closure argument list expects 1 argument, but 4 were specified'

对于以下代码:

 static func loginWithEmail(email: String, password: String, response: (token: String?) -> ()) {
    let urlString = baseURL + ResourcePath.login.description
    let parameters = [
        "email": email,
        "password": password
    ]
    Alamofire.request(.POST, urlString, parameters: parameters).responseJSON { (_, _, data, _) -> Void in
        let json = JSON(data!)
        let token = json["token"].string
        response(token: token)
    }
}

错误是指以下行:

  Alamofire.request(.POST, urlString, parameters: parameters).responseJSON { (_, _, data, _) -> Void in

我是Swift闭包的新手，不知道是否必须嵌套值才能使其有效.

I am new to swift closures and do not know if I have to nest the values in order for it to be valid.

非常感谢您的帮助.

推荐答案

闭包采用类型为Response< AnyObject，NSError>的单个参数，因此您的代码应更像这样.

The closure takes a single parameter of type Response<AnyObject, NSError> so your code should look more like this.

Alamofire.request(.POST, urlString, parameters: parameters).responseJSON { response in
    let json = JSON(response.data!)
    let token = json["token"].string
    response(token: token)
}

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