对成员Swift 3的含糊不清的引用 [英] Ambiguous reference to member Swift 3

查看:70
本文介绍了对成员Swift 3的含糊不清的引用的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在将项目从Swift 2.3迁移到Swift 3,并且遇到了预期的困难.

I am migrating my project from Swift 2.3 to Swift 3. And having difficulty as expected.

此处是使用 OAuthSwift 的OAuth函数.我试图转换

Here is a function which is being used for OAuth, using OAuthSwift. I have tried to convert

class func OAuthSwiftAuthorization(inViewController viewController: UIViewController, withOAuthInfo info:FitnessTracker, successHandler:@escaping MyOAuthNewSuccessHandler, failure: @escaping ((_ error: NSError) -> Void)) {

    let oauthswift = OAuth2Swift(
        consumerKey:    info.consumerKey,
        consumerSecret: info.consumerSecret,
        authorizeUrl:   info.authorizeUrl,
        accessTokenUrl: info.accessTokenUrl,
        responseType:   info.responseType
    )

    oauthswift.authorizeURLHandler = SafariURLHandler(viewController: viewController, oauthSwift: oauthswift)
    oauthswift.accessTokenBasicAuthentification = true
    oauthswift.allowMissingStateCheck = true

    oauthswift.authorize(withCallbackURL: URL(string: info.callBackUrl)!, scope: info.scope, state: info.state, success: { (credential, response, parameters) in

             successHandler(credential, response, parameters)
    }) { (error) in

        failure(error: error)
        print(error.localizedDescription)
    }
}

但是我在

oauthswift.authorize(withCallbackURL: URL(string: info.callBackUrl)!, scope: info.scope, state: info.state, success: { (credential, response, parameters) in

错误状态

对成员'authorize(withCallbackURL:scope:state:parameters:headers:success:failure :)'的引用不明确

Ambiguous reference to member 'authorize(withCallbackURL:scope:state:parameters:headers:success:failure:)'

这是Swift 2的工作代码.

Here is the working code from Swift 2.

    oauthswift.authorizeWithCallbackURL(
        URL(string: info.callBackUrl)!,
        scope: info.scope, state:info.state,
        success: { credential, response, parameters in

            successHandler(credientials: credential, response: response, params: parameters)
        },
        failure: { error in

            failure(error: error)
            print(error.localizedDescription)
        }
    )

更新:

我键入成功和失败后,错误不会出现.这很好:

Error does not appear unitil I type success and faliure handelrs. This complies fine:

        oauthswift.authorize(withCallbackURL: URL(string: info.callBackUrl)!, scope: info.scope, state: info.state, success: { (credential, response, parameters) in
        // successHandler(credential, response, parameters)
    }) { (erorr) in
        // failure(error: error
    }

所以请指导我,谢谢.

推荐答案

我认为此问题是由于Swift的类型推断与闭包相结合而引起的. 您可以尝试以下操作之一:

I think the problem is caused by some shortcomings of Swift's type inference in combination with closures. You could try one of the following:

例如,不要使用结尾的闭包

Either don't use trailing closures, e.g.

oauthswift.authorize(withCallbackURL: URL(string: info.callBackUrl)!, scope: info.scope, state: info.state, success: { (credential, response, parameters) in

         successHandler(credential, response, parameters)
}, failure: { (error) in

    failure(error: error)
    print(error.localizedDescription)
})

或提供明确的错误类型,例如

or provide an explicit type for error, e.g.

 oauthswift.authorize(withCallbackURL: URL(string: info.callBackUrl)!, scope: info.scope, state: info.state, success: { (credential, response, parameters) in

         successHandler(credential, response, parameters)
 }) { (error: Error) in

     failure(error: error)
     print(error.localizedDescription)
 }

这篇关于对成员Swift 3的含糊不清的引用的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆