在Swift中，如何从内存中完全删除UIView? [英] In Swift, how to remove a UIView from memory completely?

问题描述

请考虑以下代码:

class myManager {
    var aView: UIView!

    func createView() {
        aView = UIView()
    }

    func removeView() {
        aView = nil // anything else?
    }
}

如果我这样创建一个UIView，后来又想将其删除，这是正确的方法吗?我应该注意什么?

If I create a UIView like this and later I want to remove it, is this the correct way? Anything I should be aware of?

推荐答案

要取消初始化aView并将其从内存中删除，您需要使任何对此内容有强引用的东西都未引用它.这意味着您的代码的任何部分(UIKit视图堆栈的和)都不应引用它.

In order to have aView to be deinitialised and removed from memory you need to make it unreferenced by anything that keeps a strong reference to it. That means it should not be referenced by any part of your code, and by the UIKit view stack.

在您的情况下，它可能看起来像这样:

In your case it might look like this:

aView?.removeFromSuperview() // This will remove the view from view-stack
                             // (and remove a strong reference it keeps)

aView = nil                  // This will remove the reference you keep

另一方面，如果要删除视图，则可能不应该使用var aView: UIView!，而应使用var aView: UIView?.

On a side note, if you are removing the view, then you probably should not use var aView: UIView! but instead var aView: UIView?.

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