将数字应用于文本swift2中的每个字母 [英] Apply a number to each letter in text swift2
问题描述
我想比较UITextField
中为每个字母赋予数字的两个条目,然后比较两个字段中字母相加的结果.
I want to compare two entries in a UITextField
giving a number to each letter and then compare the results of the addition of the letters from both fields.
示例:
a = 1 b = 2 c = 3 d = 4 e = 5 f = 6
a=1 b=2 c=3 d=4 e=5 f=6
textfield1 = cae
textfield2 = fca
textfield1= cae
textfield2= fca
结果是:
textfield1 = 9和
textfield2 = 10
textfield1=9 and
textfield2=10
推荐答案
您可以使用每个字符的unicode标量表示形式(查找ASCII表),并将它们相加后相加-96
(例如,a -> 1
,
You could use the unicode scalar representation of each character (look up ASCII tables) and sum these shifted by -96
(such that a -> 1
, b -> 2
and so on). In the following, upper case letters will generate the same number value as lower case ones.
let foo = "cae"
let pattern = UnicodeScalar("a")..."z"
let charsAsNumbers = foo.lowercaseString.unicodeScalars
.filter { pattern ~= $0 }
let sumOfNumbers = charsAsNumbers
.reduce(0) { $0 + $1.value - 96 }
print(sumOfNumbers) // 9
或者,为简化用法,创建一个函数或String
扩展
Or, to simplify usage, create a function or String
extension
/* as a function */
func getNumberSum(foo: String) -> UInt32 {
let pattern = UnicodeScalar("a")..."z"
return foo.lowercaseString.unicodeScalars
.filter { pattern ~= $0 }
.reduce(0) { $0 + $1.value - 96 }
}
/* or an extension */
extension String {
var numberSum: UInt32 {
let pattern = UnicodeScalar("a")..."z"
return self.lowercaseString.unicodeScalars
.filter { pattern ~= $0 }
.reduce(0) { $0 + $1.value - 96 }
}
}
您的案例的用法示例:
/* example test case (using extension) */
let textField1 = UITextField()
let textField2 = UITextField()
textField1.text = "cAe"
textField2.text = "FCa"
/* example usage */
if let textFieldText1 = textField1.text,
let textFieldText2 = textField2.text {
print(textFieldText1.numberSum) // 9
print(textFieldText2.numberSum) // 10
print(textFieldText1.numberSum
== textFieldText2.numberSum) // false
}
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