Swift 2从包含字符串的数组中删除对象 [英] Swift 2 remove object from array with contains string have

问题描述

我在Swift 2中有字符串数组

I have string array in Swift 2:

var myList              : [String] = []

我内部有动态字符串，并使用*字符myList示例将其爆炸:

And I have dynamic strings inside and I explode them with * character myList examples:

   print(myList[0])  output = 2018-04-05*type2*namea
   print(myList[1])  output = 2018-04-05*type2*nameb
   print(myList[2])  output = 2018-04-05*type3*nameb
   print(myList[3])  output = 2018-04-06*type3*named

我要删除myList中具有 type3 个对象的对象:

I want to delete objects have type3 ones in myList:

如果输入的是相同日期和相同名称，并且具有 type2 一个

IF IN same date AND same name AND have type2 ones

必须是这样的字符串:

   print(myList[0])  output = 2018-04-05*type2*namea
   print(myList[1])  output = 2018-04-05*type2*nameb
   print(myList[2])  output = 2018-04-06*type3*named

下面的此项必须删除:

   print(myList[2])  output = 2018-04-05*type3*nameb

如果以前具有与日期和名称相同的type2，我想删除myList中的type3.

I want to delete type3 ones in myList if before have type2 with same date and same name basically.

说明:

2018-04-05*type2*nameb和2018-04-05*type3*nameb，具有相同的日期和相同的名称，但2018-04-05*type3*nameb之前具有 type2 (2018-04-05 * type2 * nameb)?因此2018-04-05 * type3 * nameb行必须删除

2018-04-05*type2*nameb and 2018-04-05*type3*nameb, have same date and same name but 2018-04-05*type3*nameb before have type2(2018-04-05*type2*nameb) ? so 2018-04-05*type3*nameb line must be delete

我该怎么办?

推荐答案

此游乐场代码将执行您想要的操作:

This playground code will do what you want:

//: Playground - noun: a place where people can play

import UIKit

let myList = ["2018-04-05*type2*namea",
              "2018-04-05*type2*nameb",
              "2018-04-05*type3*nameb",
              "2018-04-06*type3*named"]

//Define a class that lets us map from a string to a date, type, and name string
class ListEntry {
    let fullString: String

    //define lazy vars for all the substrings
    lazy var subStrings: [Substring] = fullString.split(separator: "*")
    lazy var dateString = subStrings[0]
    lazy var typeString = subStrings[1]
    lazy var nameString = subStrings[2]

    //Create a failable initializer that takes a full string as input 
    //and tries to break it into exactly 3 substrings
    //using the "*" sparator
    init?(fullString: String) {
        self.fullString = fullString
        if subStrings.count != 3 { return nil }
    }
}

print("---Input:---")
myList.forEach { print($0) }
print("------------")

//Map our array of strings to an array of ListEntry objects
let items = myList.compactMap { ListEntry(fullString: $0) }

//Create an output array
var  output: [String] = []

//Loop through each item in the array of ListEntry objects, getting an index for each
for (index,item) in items.enumerated() {

    //If this is the first item, or it dosn't have  type == "type3", add it to the output
    guard index > 0,
        item.typeString == "type3" else {
            print("Adding item", item.fullString)
            output.append(item.fullString)
            continue
    }
    let previous = items[index-1]

    /*
     Add this item if
        -the previous type isn't "type2"
        -the previous item's date doesn't match this one
        -the previous item's name doesn't match this one
     */
    guard previous.typeString == "type2",
        item.dateString == previous.dateString,
        item.nameString == previous.nameString else {
            print("Adding item", item.fullString)
            output.append(item.fullString)
            continue
    }
    print("Skipping item ", item.fullString)
}
print("\n---Output:---")
output.forEach { print($0) }

上面的代码输出为:

---Input:---
2018-04-05*type2*namea
2018-04-05*type2*nameb
2018-04-05*type3*nameb
2018-04-06*type3*named
------------
Adding item 2018-04-05*type2*namea
Adding item 2018-04-05*type2*nameb
Skipping item  2018-04-05*type3*nameb
Adding item 2018-04-06*type3*named

---Output:---
2018-04-05*type2*namea
2018-04-05*type2*nameb
2018-04-06*type3*named

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