如何在swiftui中使用多维字典的导航链接使代码更简单，更可重用? [英] how to make the code simpler and more reusable for navigation links with multi dimension dictionary in swiftui?

问题描述

我有一个多层字典，需要用来建立导航链接. 现在，我有一个2级深度词典:

I have a multi-level dictionary that I need use to build navigation links. Now I have a 2-level depth dictionary:

let multiDimDict: [String: [[String: [String]]]]
= ["A": [["A1": ["A11", "A12"]], ["A2": ["A21", "A22"]]],
   "B": [["B1": ["B11", "B12"]], ["B2": ["B21", "B22"]]]
    ]

我可以使用所有导航链接构建导航视图.但是，我觉得我正在以某种方式在构建导航链接中重复一些代码.问题是，如果我有一个多级字典，例如10级，我认为构建10个不同的子视图生成器以构建完整的导航视图是不明智的.知道如何减少代码吗?

I can build the navigation view with all navigation links. However, I feel that I am somehow repeating some code in building navigation links. The question is, if I have a many-level dictionary, say 10-level, I don't think it's wise to build 10 different child-view generators in order to build the complete navigation view. Any idea how to reduce the code?

struct PlayingWithMultiDimNavLink: View {

    let multiDimDict: [String: [[String: [String]]]]
    = ["A": [["A1": ["A11", "A12"]], ["A2": ["A21", "A22"]]],
       "B": [["B1": ["B11", "B12"]], ["B2": ["B21", "B22"]]]
        ]




    var body: some View {

        NavigationView{
            List {
                ForEach(multiDimDict.keys.sorted(), id: \.self) { key in

                    NavigationLink(destination: GenerateChildView(key: key, dict: self.multiDimDict)){

                        Text(key)
                    }

                }
            }
        }

    }
}

这是:first子视图生成器:

This is the :first child view generator:

struct GenerateChildView: View {

    var key: String
    var dict: [String: [[String: [String]]]]
    var infoList: [[String: [String]]]

    init(key: String, dict: [String: [[String: [String]]]]  ){
        self.key = key
        self.dict = dict
        self.infoList = dict[key]!
    }


    var body: some View {
        List{
            ForEach(infoList, id: \.self){ info in
                self.getSomeView(infoList: self.infoList)

            }
        }

}


    func getSomeView(infoList: [[String: [String]]] )-> AnyView{

        let dictToUse = infoList[0]
        return AnyView(
            ForEach(dictToUse.keys.sorted(), id: \.self){ key2 in

                    NavigationLink(destination: GenerateChildView2(infoList: dictToUse[key2]!)){
                        Text(key2)
                    }
                }


        )

    }

最后一个子视图生成器:

The last child-view generator:

struct GenerateChildView2: View {

    var infoList: [String]

    init(infoList: [String]){
        self.infoList = infoList
    }

    var body: some View {

        List{

            ForEach(infoList, id:\.self){ content in

                Text(content)
            }

        }


    }
}

推荐答案

我将首先放弃使用字典，而使用提供更有用模型的简单递归结构:

I would start by abandoning the use of a dictionary and use a simple recursive struct that provides a more useful model:

struct Item: Identifiable {
    let id = UUID()
    var title: String
    var children: [Item] = []
}

然后，您可以定义一个递归View来显示此模型:

Then you can define a recursive View to display this model:

struct NavView: View { 
    var item: Item

    var body: some View {
        NavigationView {
            List {
                ForEach(item.children) { child in
                    if child.children.isEmpty {
                        Text(child.title)
                    } else {  
                        NavigationLink(destination: NavView(item:child)) {
                            Text(child.title)
                        }
                    }
                }
            }.navigationBarTitle(item.title)
        }
    }
}

然后，您可以根据需要创建层次结构，并将根传递给视图:

Then you can create your hierarchy as required and pass the root to your view:

let root = Item(title:"",children:
    [Item(title:"A",children:
        [Item(title:"A1", children:
            [Item(title:"A11"),Item(title:"A12")]
            )]),
          Item(title:"B",children:
            [Item(title:"B1"),Item(title:"B2")]
        )]
)

NavView(item:root))

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