是否可以为我的linux功能复制命令的制表符完成? [英] Is it possible to copy the tab completion of a command for my linux function?

问题描述

假设我有一个名为 magic 的bash shell函数.我想定义一个制表符完成功能 _magic ，该功能将允许 magic 搭载任何给定命令的制表符完成功能(如果可用).换句话说，我希望魔术能够执行以下操作:

Let's say I have a bash shell function named magic. I want to define a tab completion function _magic which would allow magic to piggyback on the tab completion functions of any given command (if available). In other words, I want magic to be able to do something like this:

~ $ magic git ... <search for _git and use it if found>
~ $ magic cd ... <search for _cd and use it if found>
~ $ magic some-cmd ... <search for _some-cmd and use it if found>

我似乎无法在网上找到任何可以帮助我使用compgen，complete等实现此目标的东西.这是否有可能?提前致谢.

I can't seem to find anything online that would help me achieve this using compgen, complete etc. Is this even possible? Thanks in advance.

推荐答案

有许多这样的(伪?)命令都需要这样做.例如time，nice，strace等.
它们都使用相同的命令完成:_command.因此，不要重新发明轮子. :)

There are many such (pseudo?) commands, that need this. e.g. time, nice, strace etc.
They all use the same command completion: _command. So, don't re-invent the wheel. :)

如果可以，请尝试在您的bash终端中运行它:

Try running this in your bash terminal, if this work:

complete -F _command magic

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