try-with-resources中的内容是否包含括号中的代码? [英] Does the catch in try-with-resources cover the code in parentheses?

问题描述

从文档不清楚，如果<try-with-resources之后的c0>是否涵盖初始化部分.

It is unclear from the documentation if a catch following a try-with-resources covers the initialization part or not.

换句话说，给出以下代码片段:

In other words, given this code fragment:

    try (InputStream in = getSomeStream()) {
        System.out.println(in.read());
    } catch (IOException e) {
        System.err.println("IOException: " + e.getMessage());
    }

如果在getSomeStream()内部抛出IOException，会调用我的catch吗?

Would my catch be invoked if an IOException is thrown inside getSomeStream()?

还是catch仅覆盖大括号内的块，即System.out.println(in.read())?

Or does the catch only cover the block inside curly braces, i.e. System.out.println(in.read())?

推荐答案

来自

From the JLS, your example is an extended try-with-resources.

try-with-resources语句，至少包含一个catch子句和/或 finally子句称为扩展的try-with-resources语句.

A try-with-resources statement with at least one catch clause and/or a finally clause is called an extended try-with-resources statement.

在这种情况下:

翻译的效果是放入资源说明 在try语句内部". 这允许扩展的catch子句 try-with-resources语句捕获由于而导致的异常 自动初始化或关闭任何资源.

The effect of the translation is to put the resource specification "inside" the try statement. This allows a catch clause of an extended try-with-resources statement to catch an exception due to the automatic initialization or closing of any resource.

是的，您的catch块将捕获该异常.

So yes, the exception will be caught by your catch block.

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