如何在bash中对逗号分隔的值进行排序? [英] How to sort comma separated values in bash?

问题描述

我有一些数字

7, 15, 6, 2, -9

我想在bash中这样排序(从命令行或脚本文件)

I want to sort it like this in bash(from command line or either a script file)

-9, 2, 6, 7, 15

我该怎么做?我无法使用sort命令获得此信息.

How can I do this? I am unable to get this using sort command.

推荐答案

echo "7, 15, 6, 2, -9" | sed -e $'s/,/\\\n/g' | sort -n | tr '\n' ',' | sed 's/.$//'

1. sed -e $'s/,/\\\n/g':用于通过逗号将字符串分成几行.
2. sort -n:然后您可以使用按数字排序
3. tr '\n' ',':将换行符分隔为逗号.
4. sed 's/.$//':删除尾巴逗号.

1. sed -e $'s/,/\\\n/g': For splitting string into lines by comma.
2. sort -n: Then you can use sort by number
3. tr '\n' ',': Covert newline separator back to comma.
4. sed 's/.$//': Removing tailing comma.

不够优雅，但应该可以:p

Not elegant enough, but it should work :p

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