通过UIMenuController的UIMenuItem传递值 [英] Pass value through UIMenuItem of UIMenuController

问题描述

我正在使用以下方法在UITableViewCell中长按显示菜单.

I am using following method to show menu on long press in UITableViewCell.

我需要通过按Delete菜单项将值传递给-(void)numberDelete方法.

I have need to pass a value pressing Delete menu Item to -(void)numberDelete method.

-(void)handleLongPress:(UILongPressGestureRecognizer *)gestureRecognizer {

    if(gestureRecognizer.state == UIGestureRecognizerStateBegan) {

        CGPoint p = [gestureRecognizer locationInView: self.pullTableView];
        NSIndexPath *indexPath = [self.pullTableView indexPathForRowAtPoint:p];
        if(indexPath != nil) {

            [self becomeFirstResponder];
            NSInteger *row = indexPath.row;

            //need to pass this row value through @selector(numberDelete:)

            UIMenuItem *delete = [[UIMenuItem alloc] initWithTitle:@"Delete" action:@selector(numberDelete:)];

            UIMenuController *menu = [UIMenuController sharedMenuController];
            [menu setMenuItems:[NSArray arrayWithObjects:delete, nil]];
            [menu setTargetRect:[self.pullTableView rectForRowAtIndexPath:indexPath] inView:self.pullTableView];
            [menu setMenuVisible:YES animated:YES];
        }

    }

}

-(void)numberDelete:(id)sender {
   //receive value of row here
}

-(BOOL)canBecomeFirstResponder {
    return YES;
}

-(BOOL)canPerformAction:(SEL)action withSender:(id)sender {
    if (action == @selector(customDelete:) ){
        return YES;
    }
    return NO;
}

推荐答案

如此简单，只需创建类型为UIMenuItem的类，在其中添加属性，然后使用您的UIMenuItem class而不是实际的UIMenuItem.看看如何.

So simple, just create a class of type UIMenuItem, add property in it, and use your UIMenuItem class instead of actual UIMenuItem. See how.

创建一个类，例如type UIMenuItem的MyMenuItem.

MyMenuItem.h

MyMenuItem.h

#import <UIKit/UIKit.h>

@interface MyMenuItem : UIMenuItem
@property(nonatomic, strong)NSIndexPath *indexPath;
@end

MyMenuItem.m

MyMenuItem.m

#import "MyMenuItem.h"

@implementation MyMenuItem

@end

然后

{
    MyMenuItem *deleteMenuItem = [[MyMenuItem alloc] initWithTitle:@"Delete" action:@selector(numberDelete:)];
    deleteMenuItem.indexPath=indexPath;//Assign to property

    UIMenuController *menu = [UIMenuController sharedMenuController];
    [menu setMenuItems:[NSArray arrayWithObjects:deleteMenuItem, nil]];
    [menu setTargetRect:[self.pullTableView rectForRowAtIndexPath:indexPath] inView:self.pullTableView];
    [menu setMenuVisible:YES animated:YES];
}



-(void)numberDelete:(id)sender {
   //receive value of row here. The sender in iOS 7 is an instance of UIMenuController.
   UIMenuController *targetSender = (UIMenuController *)sender ;
   MyMenuItem *menuItem=(MyMenuItem *)[targetSender.menuItems firstObject]; 

   NSLog(@"%d",menuItem.indexPath.row); 
}

希望对您有帮助.

干杯.

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