urlparse.urlparse在方案之后返回3'/'而不是2 [英] urlparse.urlparse returning 3 '/' instead of 2 after scheme

问题描述

如果缺少，我想在给定的URL字符串前添加'http'方案名称.否则，请不要使用url，所以我认为urlparse是执行此操作的正确方法.但是，只要没有方案，并且我使用get url，我就会在方案和域之间得到///而不是'//'.

I'd like to add the 'http' scheme name in front of a given url string if it's missing. Otherwise, leave the url alone so I thought urlparse was the right way to do this. But whenever there's no scheme and I use get url, I get /// instead of '//' between the scheme and domain.

>>> t = urlparse.urlparse('www.example.com', 'http')
>>> t.geturl()
'http:///www.example.com' # three ///

如何转换此网址，使其看起来像这样:

How do I convert this url so it actually looks like:

'http://www.example.com' # two //

推荐答案

简短的回答(但这有点重言自语):

Short answer (but it's a bit tautological):

>>> urlparse.urlparse("http://www.example.com").geturl()
'http://www.example.com'

在您的示例代码中，主机名被解析为路径而不是网络位置:

In your example code, the hostname is parsed as a path not a network location:

>>> urlparse.urlparse("www.example.com/go")
ParseResult(scheme='', netloc='', path='www.example.com/go', params='', \
    query='', fragment='')

>>> urlparse.urlparse("http://www.example.com/go")
ParseResult(scheme='http', netloc='www.example.com', path='/go', params='', \
    query='', fragment='')

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