查找字符串是否以列表的可变长度前缀之一开头 [英] Finding whether a string starts with one of a list's variable-length prefixes

问题描述

我需要找出名称是否以列表的前缀开头，然后将其删除，例如:

I need to find out whether a name starts with any of a list's prefixes and then remove it, like:

if name[:2] in ["i_", "c_", "m_", "l_", "d_", "t_", "e_", "b_"]:
    name = name[2:]

以上内容仅适用于长度为2的列表前缀.对于可变长度前缀，我需要相同的功能.

The above only works for list prefixes with a length of two. I need the same functionality for variable-length prefixes.

它如何有效地完成(代码少，性能好)?

How is it done efficiently (little code and good performance)?

一个for循环在每个前缀上进行迭代，然后检查name.startswith(prefix)以根据前缀的长度最终对名称进行切片，但这是很多代码，可能效率低下，并且是非Pythonic的".

A for loop iterating over each prefix and then checking name.startswith(prefix) to finally slice the name according to the length of the prefix works, but it's a lot of code, probably inefficient, and "non-Pythonic".

有人有很好的解决方案吗?

Does anybody have a nice solution?

推荐答案

有点难以理解，但这可行:

A bit hard to read, but this works:

name=name[len(filter(name.startswith,prefixes+[''])[0]):]

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