将版本号部分与正则表达式匹配 [英] Matching version number parts with regular expressions

问题描述

我正在尝试将版本号(Major.Minor.Build.Revision)的部分与C#正则表达式匹配.但是，我对编写Regex非常陌生，即使使用Expresso也被证明有点困难.现在，我有这个:

I'm trying to match the parts of a version number (Major.Minor.Build.Revision) with C# regular expressions. However, I'm pretty new to writing Regex and even using Expresso is proving to be a little difficult. Right now, I have this:

(?<Major>\d*)\.(?<Minor>\d*)\.(?<Build>\d*)\.(?<Revision>\d*)

这可行，但是要求版本号的每个部分都存在.我还想匹配以下版本:

This works, but requires that every part of the version number exists. What I would like to do is also match versions like:

2.13

在这种情况下，构建"和修订"组需要返回空值.如果我要解决所有这些错误，请随时提出一个更好的方法.

In this case, the Build and Revision groups need to return null values. Feel free to suggest a better method if I'm going about this all wrong.

推荐答案

(?<Major>\d*)\.(?<Minor>\d*)(\.(?<Build>\d*)(\.(?<Revision>\d*))?)?

将第三部分和第四部分设为可选.

Makes the third and fourth parts optional.

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