Xamarin表单绑定-访问父属性 [英] Xamarin Forms Binding - access parent property

问题描述

我无法访问页面的ViewModel属性以将其绑定到IsVisible属性.如果不设置BindingContext，则只能绑定它.有没有办法在设置BindingContext的同时访问页面的viewmodel/root属性?

I cannot access the Page's ViewModel property in order to bind it to IsVisible Property. I can only bind it if I don't set the BindingContext. Is there a way I can access the page's viewmodel/root property while also setting the BindingContext?

页面XAML:

<eventViews:EventInfoWidget BindingContext="{Binding EventViewModel}" IsVisible="{Binding IsEventInfoWidgetEnabled}" />
<eventViews:AvailableShiftInfoWidget BindingContext="{Binding EventViewModel}" IsVisible="{Binding IsAvailableShiftInfoWidgetEnabled}"></eventViews:AvailableShiftInfoWidget>

ViewModel:

ViewModel:

public EventViewModel EventViewModel { get; }
public bool IsEventInfoWidgetEnabled => _IsEventInfoWidgetEnabled.Value;
public bool IsAvailableShiftInfoWidgetEnabled => _IsAvailableShiftInfoWidgetEnabled.Value;

IsVisibile属性只能绑定到EventViewModel对象属性，但是我想将其绑定到页面的viewmodel

The IsVisibile Property can only be bind to the EventViewModel Object Properties, but I would like to bind it to the page's viewmodel

• IsEventInfoWidgetEnabled
• IsAvailableShiftInfoWidgetEnabled

推荐答案

找到解决方案后，您必须指定源，然后设置属性的路径.

Found the solution, you have to specify the source and then set the path to the property.

首先设置页面名称

<pages:AppContentPage 
xmlns="http://xamarin.com/schemas/2014/forms" 
x:Name="ShiftPage">

之后，只需将IsVisible属性绑定到正确的源

After that just bind IsVisible Property to the right source

IsVisible="{Binding Source={x:Reference ShiftPage}, Path=BindingContext.IsEventInfoWidgetEnabled }"

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