Swift 1.2(Xcode 6.3)删除了布尔值的xor'^'运算符? [英] Swift 1.2 (Xcode 6.3) removed xor '^' operator for Bool value?

问题描述

此示例代码在Xcode 6.3上...

This sample code on Xcode 6.3 ...

var str1 = ""
var str2 = ""
if str1.isEmpty ^ str2.isEmpty {
  // do something.
}

显示以下错误.

'^' is unavailable: use the '!=' operator instead

我在Apple文档中找不到规范. 是这个规范(我必须把它统统包起来)吗?

I cannot find the spec in Apple documentation. Is this specification (and I'll have to lump it)?

推荐答案

这显然是故意的:

$ echo ':print_module Swift' | swift -deprecated-integrated-repl | fgrep "use the '!=' operator instead"

显示:

@availability(*, unavailable, message="use the '!=' operator instead") func ^=(inout lhs: Bool, rhs: Bool)
@availability(*, unavailable, message="use the '!=' operator instead") func ^(lhs: Bool, rhs: Bool) -> Bool

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