解析时XmlSlurper问题 [英] XmlSlurper Issue while Parsing

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本文介绍了解析时XmlSlurper问题的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我的XML如下,

<div class="storeContainer">
      <div class="storeCount">50</div>
      <div class="mapAddress" id="store50">
         <h4 onclick="changeMap(50,38.872432,-78.530463);">Woodstock, VA</h4>
         <h5>Woodstock Square</h5>467 West Reservoir Road
<br/>540-459-7505
<br/>
         <a href="https://maps.google.com/maps?saddr=geo&amp;daddr=467+West+Reservoir+Road+Woodstock+VA+22664&amp;sll=38.872432,-78.530463&amp;sspn=0.011265,0.014098&amp;z=12"
            class="getDirections">Get Directions</a>
      </div>
   </div>
</div>

我想阅读地址详细信息,并且正在使用

I wanted to read address details and am using the

def envelope = new XmlSlurper().parseText(response.toString());
        envelope.'**'
        .each {
            println it.h4.text()
            println it.h5.text()

            println it.a.@'href'    
        }

获取值,但我不知道如何获取水库西路467号 540-459-7505

to get the values but i don't know how to get 467 West Reservoir Road and 540-459-7505

推荐答案

如果切换到XmlParser,则可以执行以下操作:

If you switch to XmlParser, you can do:

def envelope = new XmlParser().parseText(xml);

envelope.'**'.find { it.@class == 'mapAddress' }.with { node ->
    println h4.text()
    println h5.text()
    println a.@'href'
    println node.children().findAll { it.getClass() == String }*.trim()
}

这篇关于解析时XmlSlurper问题的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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