Xpath-如何选择相关的表亲数据 [英] Xpath - How to select related cousin data
问题描述
<html>
<table border="1">
<tbody>
<tr>
<td>
<table border="1">
<tbody>
<tr>
<th>aaa</th>
<th>bbb</th>
<th>ccc</th>
<th>ddd</th>
<th>eee</th>
<th>fff</th>
</tr>
<tr>
<td>111</td>
<td>222</td>
<td>333</td>
<td>444</td>
<td>555</td>
<td>666</td>
</tr>
</tbody>
</table>
</td>
</tr>
</tbody>
</table>
</html>
如何使用xpath选择特定的相关表亲数据，所需的输出为:
How can i select specific related cousin data using xpath, The desired output would be be:
<th>aaa</th>
<th>ccc</th>
<th>fff</th>
<td>111</td>
<td>333</th>
<td>666</td>
xpath最重要的方面是我希望能够包含或排除某些<th>标签及其对应的<td>标签
The most important aspect of the xpath is that i am looking to be able to include or exclude certain <th> tags and their corresponding <td>tags
因此，根据目前为止的答案，我最接近的是:
So based on the answers so far the closest I have is:
//th[not(contains(text(), "ddd"))] | //tr[2]/td[not(position()=4)]
有没有不使用position()=4而是引用相应的th标签的任何方式
Is there any way of not explicitly using position()=4 but instead reference the corresponding th tag
推荐答案
我不确定这是最佳解决方案，但您可以尝试
I'm not sure that this is the best solution, but you might try
//th[not(.="bbb") and not(.="ddd") and not(.="eee")] | //tr[2]/td[not(position()=index-of(//th, "bbb")) and not(position()=index-of(//th, "ddd")) and not(position()=index-of(//th, "eee"))]
或更短的版本
//th[not(.=("bbb", "ddd", "eee"))]| //tr[2]/td[not(position()=(index-of(//th, "bbb"), index-of(//th, "ddd"),index-of(//th, "eee")))]
您可以避免使用复杂的XPath表达式来获取所需的输出.尝试改用Python + Selenium功能:
You can avoid using complicated XPath expressions to get required output. Try to use Python + Selenium features instead:
# Get list of th elements
th_elements = driver.find_elements_by_xpath('//th')
# Get list of td elements
td_elements = driver.find_elements_by_xpath('//tr[2]/td')
# Get indexes of required th elements - [0, 2, 5]
ok_index = [th_elements.index(i) for i in th_elements if i.text not in ('bbb', 'ddd', 'eee')]
for i in ok_index:
print(th_elements[i].text)
for i in ok_index:
print(td_elements[i].text)
输出为
'aaa'
'ccc'
'fff'
'111'
'333'
'666'
如果您需要XPath 1.0解决方案:
//th[not(.=("bbb", "ddd", "eee"))]| //tr[2]/td[not(position()=(count(//th[.="bbb"]/preceding-sibling::th)+1, count(//th[.="ddd"]/preceding-sibling::th)+1, count(//th[.="eee"]/preceding-sibling::th)+1))]
这篇关于Xpath-如何选择相关的表亲数据的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
