如何使用YQL合并多个其余查询? [英] How do I combine multiple rest queries using YQL?

问题描述

例如，我想将多个查询，其余查询组合在一起.现在，我一次用不同的URL执行以下代码.我认为在我的情况下，最终一次请求10个链接会更快.感谢您的帮助.

For example I would like to combine multiple queries rest queries together. Right now I do the following code with different URLs one at a time. I think it would be faster to ultimately make one request for 10 links in my case. Any help is appreciated.

use 'http://javarants.com/yql/javascript.xml'as j; select * from j where code='response.object = y.rest("http://feedproxy.google.com/~r/Techcrunch/~3/P%5FqWQXyAPU/").followRedirects(false).get().headers.location;'

推荐答案

一种可能性是为此构建自己的YQL表，然后在<execute>...</execute>块中执行所需的javascript.

One possibility would be to build your own YQL table for this, which then executes the javascript you need in an <execute>...</execute> block.

想到的另一种选择是query.multi YQL表.

The other alternative that comes to mind is the query.multi YQL table.

不确定您要执行的操作，但是可以尝试一下.请勿更改结尾的引号()，它必须在最后一个分号后直接保留(这是我刚刚遇到的一个错误，持续了几分钟).

Not sure that does what you want it do to but you can give it a try. Don't change the trailing quotation mark ("), it needs to stay directly after the last semicolon (this was a mistake that I just struggled with for some minutes).

USE 'http://javarants.com/yql/javascript.xml' AS j; 

SELECT * FROM query.multi WHERE queries="
select * from j where code='response.object = y.rest(\\'http://feedproxy.google.com/~r/Techcrunch/~3/P%5FqWQXyAPU/\\').followRedirects(false).get().headers';
select * from j where code='response.object = y.rest(\\'http://stackoverflow.com/feeds/question/4917144\\').followRedirects(false).get().headers';"

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