Zend Framework:在一个布局中渲染多个视图 [英] Zend Framework: Render multiple Views in one Layout
问题描述
我想使用Zend_Layout生成一个动态网站.
I want to generate a dynamic site using Zend_Layout.
我的布局(/application/layouts/scripts/layout.phtml)包含以下几行:
My layout (/application/layouts/scripts/layout.phtml) contains the following lines:
...
<body>
<?php echo $this->render('header.phtml') ?>
<div id="content"><?php echo $this->layout()->content ?></div>
<?php echo $this->render('footer.phtml') ?>
</body>
...
如果我浏览到索引控制器索引操作-Zend会自动在$ this-> layout()-> content内呈现索引视图(application/views/scripts/index/index.phtml).
If i browse to my index controller index action - Zend renders the index view (application/views/scripts/index/index.phtml) inside of $this->layout()->content automatically.
现在，我想在布局中将视图呈现给不同的控制器动作. 因此，我使用操作登录名生成了一个新的控制器身份验证，其中显示了登录表单.
Now i want to render the views of to different controller actions in the layout. So i generate a new controller auth with an action login that shows a login form.
我将布局更改为:
...
<body>
<?php echo $this->render('header.phtml') ?>
<div id="content"><?php echo $this->layout()->content ?></div>
<div id="login"><?php echo $this->layout()->login ?></div>
<?php echo $this->render('footer.phtml') ?>
</body>
...
当我浏览到索引/索引时，我想在此操作中定义zend应该在$ this-> layout()-> login内呈现auth/login视图，例如在$ this-> layout内呈现news/list ()->内容.
When i browse to index/index, i want to define in this action that zend should render auth/login view inside $this->layout()->login and for example news/list inside of $this->layout()->content.
索引/索引不仅仅是一种页面布局- 并进行身份验证/登录和新闻/列出一种小工具
index/index is than a kind of a page layout - and auth/login and news/list a kind of widget
该怎么做?
推荐答案
第一个建议是不惜一切代价避免使用Action视图帮助程序，无论如何它可能会在ZF 2.0中被删除. ( ZF-5840 )(
First advice is to avoid the Action view helper at all costs, it will probably be removed in ZF 2.0 anyway. (ZF-5840) (Why the actionstack is evil)
这与我问的问题-和bittarman的有关答案非常有用.实现类似功能的最佳方法是拥有一个可以生成登录"区域的视图助手.例如My_View_Helper_Login.然后，您的布局可以调用$this->login()，user/login的视图脚本也可以调用.只要使index/index呈现来自news/list的内容，就将请求转发到另一个控制器/来自控制器的操作. $this->_forward('list', 'news');
This is related to a question I asked - and bittarman's answer is pretty useful. The best way to implement something like that is to have a view helper that can generate your "login" area. My_View_Helper_Login for instance. Then your layout can call $this->login(), and so can the view script for user/login. As far as having index/index render the content from news/list just forward the request to the other controller/action from the controller. $this->_forward('list', 'news');
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