创建React App Typescript不会加载d.ts文件 [英] Create react app typescript does not load d.ts file

问题描述

我已经使用create react app typescript创建了一个项目.我有一些d.ts文件，其中定义了接口类型和枚举.当我运行启动脚本时.它无法加载d.ts文件.

I have created a project using create react app typescript. I have a few d.ts files where I have defined interfaces types and enums. When I run start script. It is not able to load the d.ts files.

以下是我的tsconfig文件.

following is my tsconfig file.

{
  "compilerOptions": {
    "target": "es6",
    "lib": [
      "dom",
      "dom.iterable",
      "es2017"
    ],
    "allowJs": true,
    "skipLibCheck": false,
    "esModuleInterop": true,
    "allowSyntheticDefaultImports": true,
    "strict": false,
    "forceConsistentCasingInFileNames": true,
    "module": "esnext",
    "moduleResolution": "node",
    "resolveJsonModule": true,
    "isolatedModules": true,
    "noEmit": true,
    "jsx": "preserve",
    "pretty": true,
    "preserveConstEnums": true,
    "typeRoots": [
      "./node_modules/@types",
      "src/*"
    ]
  },
  "include": [
    "src/*"
  ]
}

typeRoot指向src/*，其中我有d.ts文件，但没有d.ts加载.我得到以下错误:

typeRoot points to src/* , where i have my d.ts files but none of the d.ts is loaded. and I get following error:

类型错误:找不到名称"IAlarmsDetails". TS2304

Type error: Cannot find name 'IAlarmsDetails'. TS2304

interface IAlarmProps {
        alarm: IAlarmsDetails;
}       

这是Alarm.d.ts之一中IAlarmsDetails的声明

This is the declaration for IAlarmsDetails in one of Alarm.d.ts

declare type IAlarmsList = IAlarmsDetails[];

请让我知道我在这里想念的东西. 我不想使用弹出选项并编写自己的构建配置.

Please let me know what I'm missing here. I do not want to use eject option and write my own build config.

推荐答案

似乎在create-react-app(版本3.0.1)中直接使用.d.ts文件的唯一方法是为其命名global.d.ts并将其放在src目录中:

It seems that the only way to use a .d.ts file out of the box with create-react-app (version 3.0.1) is to name it global.d.ts and put it in the src directory:

src/global.d.ts

我不确定为什么没有在任何地方记录此规则，但这是我能够使它生效的唯一方法.

I'm not sure why this rule isn't documented anywhere but that was the only way I was able to get it to work.

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