AWS |模块中的语法错误:语法无效 [英] AWS | Syntax error in module': invalid syntax
问题描述
我创建了python脚本,该脚本以zip文件的形式上传到AWS Lambda函数中,其中捆绑了Stompy库.
I have created python script which is uploaded as a zip file in AWS Lambda function with stompy libraries bundled in them.
python 2.7的日志:-
Logs for python 2.7:-
Response:
null
Request ID:
"c334839f-ee46-11e8-8970-612f1dc92e41"
Function Logs:
START RequestId: c334839f-ee46-11e8-8970-612f1dc92e41 Version: $LATEST
CONNECTION Started
CONNECTION established
CONNECTION Subscribed
[WARNING] 2018-11-22T11:07:12.798Z c334839f-ee46-11e8-8970-612f1dc92e41 Unknown response frame type: '' (frame length was 3)
END RequestId: c334839f-ee46-11e8-8970-612f1dc92e41
REPORT RequestId: c334839f-ee46-11e8-8970-612f1dc92e41 Duration: 10027.75 ms Billed Duration: 10100 ms Memory Size: 128 MB Max Memory Used: 30 MB
我的代码:-
import time
import boto3
import stomp
kinesis_client = boto3.client('kinesis')
class Listener(stomp.ConnectionListener):
msg_list = []
def on_error(self, headers, message):
print('received an error "%s"' % message)
def on_message(self, headers, message):
print('received a message "%s"' % message)
kinesis_client.put_record(
StreamName='Purchasing',
Data=u'{}\r\n'.format(message).encode('utf-8'),
PartitionKey='0'
)
def lambda_handler(event, context):
conn = stomp.Connection(host_and_ports=[('b-4714-4441-8166-47aae158281a-1.mq.eu-central-1.amazonaws.com', 8162)])
lst = Listener()
conn.set_listener('Listener', Listener())
conn.start()
conn.connect(login='test_mq', passcode='test_mq')
conn.subscribe(destination='/queue/Purchasing', id='b-4714-4441-8166-47aae158281a', ack='auto')
message = lst.msg_list
print('Waiting for messages "%s"' % message)
time.sleep(10)
conn.disconnect()
return ''
我不确定为什么我的消息没有显示在输出中,而是总是显示"Response:null".
I am not sure why my message is not showing up in my output,instead it always shows up "Response: null".
推荐答案
EDIT :如@Petesh所指出的,该问题来自stompy
(外部库),尚未移植到Python3.
EDIT: As pointed by @Petesh, the issue comes from stompy
(external library), which hasn't been ported to Python3.
如果您查看源代码,则可以找到以下内容:
If you check the source code, you can find this:
except socket.timeout, exc:
这是python3 +的无效语法
which is invalid syntax for python3+
如果您在python3.6/3.7环境中运行Lambda,则语法无效.
If you run your Lambdas in python3.6/3.7 environment, the syntax is invalid.
如果选择python 2.7,问题可能会消失,但是您还必须调整代码,库等.
The issue might go away if you choose python 2.7, but you will also have to adjust your code, libraries, etc.
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