如何将数组的所有成员初始化为相同的值? [英] How to initialize all members of an array to the same value?

问题描述

我在 C 中有一个大型阵列(如果有所不同，则不是 C ++ ).我想初始化所有具有相同值的成员.

I have a large array in C (not C++ if that makes a difference). I want to initialize all members of the same value.

我可以发誓，我曾经知道一种简单的方法来做到这一点.我可以使用memset()，但是没有办法直接在C语法中内置吗?

I could swear I once knew a simple way to do this. I could use memset() in my case, but isn't there a way to do this that is built right into the C syntax?

推荐答案

除非该值为0(在这种情况下，您可以省略初始化器的某些部分 并且相应的元素将被初始化为0)，没有简单的方法.

Unless that value is 0 (in which case you can omit some part of the initializer and the corresponding elements will be initialized to 0), there's no easy way.

不过，请不要忽略明显的解决方案:

Don't overlook the obvious solution, though:

int myArray[10] = { 5, 5, 5, 5, 5, 5, 5, 5, 5, 5 };

缺少值的元素将初始化为0:

Elements with missing values will be initialized to 0:

int myArray[10] = { 1, 2 }; // initialize to 1,2,0,0,0...

因此，这会将所有元素初始化为0:

So this will initialize all elements to 0:

int myArray[10] = { 0 }; // all elements 0

在C ++中，空的初始化列表还将所有元素初始化为0. 对于C:不允许

In C++, an empty initialization list will also initialize every element to 0. This is not allowed with C:

int myArray[10] = {}; // all elements 0 in C++

请记住，如果没有，则具有静态存储持续时间的对象将初始化为0 指定了初始化程序:

Remember that objects with static storage duration will initialize to 0 if no initializer is specified:

static int myArray[10]; // all elements 0

"0"并不一定意味着全零"，因此使用上面的是 比memset()更好，更可移植. (浮点值将为 初始化为+0，指向空值的指针等)

And that "0" doesn't necessarily mean "all-bits-zero", so using the above is better and more portable than memset(). (Floating point values will be initialized to +0, pointers to null value, etc.)

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