在PowerShell中选择数组的所有对象上一个属性的值 [英] Select the values of one property on all objects of an array in PowerShell

问题描述

比方说，我们有一个对象数组$ objects.假设这些对象具有名称"属性.

Let's say we have an array of objects $objects. Let's say these objects have a "Name" property.

这就是我想做的

 $results = @()
 $objects | %{ $results += $_.Name }

这可行，但是可以用更好的方法做到吗?

This works, but can it be done in a better way?

如果我做类似的事情:

 $results = objects | select Name

$results是具有Name属性的对象的数组.我希望$ results包含一个Names数组.

$results is an array of objects having a Name property. I want $results to contain an array of Names.

有更好的方法吗?

推荐答案

我认为您也许可以使用Select-Object的ExpandProperty参数.

I think you might be able to use the ExpandProperty parameter of Select-Object.

例如，要获取当前目录的列表并仅显示Name属性，可以执行以下操作:

For example, to get the list of the current directory and just have the Name property displayed, one would do the following:

ls | select -Property Name

这仍然返回DirectoryInfo或FileInfo对象.您始终可以通过管道连接到获取成员来检查通过管道的类型>(别名gm).

This is still returning DirectoryInfo or FileInfo objects. You can always inspect the type coming through the pipeline by piping to Get-Member (alias gm).

ls | select -Property Name | gm

因此，要将对象扩展为要查看的属性类型的对象，可以执行以下操作:

So, to expand the object to be that of the type of property you're looking at, you can do the following:

ls | select -ExpandProperty Name

对于您而言，您可以执行以下操作以使变量为字符串数组，其中字符串为Name属性:

In your case, you can just do the following to have a variable be an array of strings, where the strings are the Name property:

$objects = ls | select -ExpandProperty Name

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