如何将切片转换为数组引用? [英] How to convert a slice into an array reference?

问题描述

我有一个&[u8]，并且想将其转换为&[u8; 3]，而不进行复制.它应该引用原始数组.我该怎么办?

I have an &[u8] and would like to turn it into an &[u8; 3] without copying. It should reference the original array. How can I do this?

推荐答案

从Rust 1.34开始，您可以使用TryFrom/TryInto:

As of Rust 1.34, you can use TryFrom / TryInto:

use std::convert::TryFrom;

fn example(slice: &[u8]) {
    let array = <&[u8; 3]>::try_from(slice);
    println!("{:?}", array);
}

fn example_mut(slice: &mut [u8]) {
    let array = <&mut [u8; 3]>::try_from(slice);
    println!("{:?}", array);
}

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