在Bash中将定界字符串读入数组 [英] Reading a delimited string into an array in Bash

问题描述

我有一个变量，其中包含一个以空格分隔的字符串:

I have a variable which contains a space-delimited string:

line="1 1.50 string"

我想用空格作为分隔符分割该字符串并将结果存储在数组中，以便执行以下操作:

I want to split that string with space as a delimiter and store the result in an array, so that the following:

echo ${arr[0]}
echo ${arr[1]}
echo ${arr[2]}

输出

1
1.50
string

我在某个地方找到了行不通的解决方案:

Somewhere I found a solution which doesn't work:

arr=$(echo ${line})

如果在此之后运行上面的echo语句，则会得到:

If I run the echo statements above after this, I get:

1 1.50 string
[empty line]
[empty line]

我也尝试过

IFS=" "
arr=$(echo ${line})

具有相同的结果.有人可以帮忙吗?

with the same result. Can someone help, please?

推荐答案

要将字符串转换为数组，请使用

In order to convert a string into an array, please use

arr=($line)

或

read -a arr <<< $line

至关重要的是不要使用引号，因为这样做可以解决问题.

It is crucial not to use quotes since this does the trick.

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