如何使用filter()方法从JavaScript中的数组数组中获取不同的值? [英] How to get distinct values from an array of arrays in JavaScript using the filter() method?

问题描述

我有一个像这样的数组:

I have an array like this:

let x = [[1, 2], [3, 4], [1, 2], [2, 1]];

我该怎么办才能检索没有重复项的数组?

What should I do to retrieve an array without the duplicates?

[[1, 2], [3, 4], [2, 1]];

我想使用过滤器方法.我试过了，但是没用:

I would like to use the filter method. I tried this but it doesn't work:

x.filter((value,index,self) => (self.indexOf(value) === index))

正如我指定要使用过滤器方法一样，我不认为这个问题是重复的.另外，我得到了几个有趣的答案.

as I specified to use the filter method, I don't think this question is a duplicate. Also, I got several interesting answers.

推荐答案

尝试将内部数组转换为字符串，然后过滤重复对象并再次解析该字符串.

Try converting the inner arrays to a string, then filter the dupes and parse the string again.

let x = [[1, 2], [3, 4], [1, 2]];

var unique = x.map(ar=>JSON.stringify(ar))
  .filter((itm, idx, arr) => arr.indexOf(itm) === idx)
  .map(str=>JSON.parse(str));

console.log(unique);

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