在数组上使用字符串的switch语句 [英] Switch statement using string on an array

问题描述

#include<stdio.h>

int main(){

    char name[20];

    printf("enter a name ");
    scanf("%s",name);
    switch(name[20]){
        case "kevin" : 
        printf("hello");
        break;
    }
    printf("%s",name);
    getch();
}

看来这是行不通的.这可能吗?我的意思是，有什么方法可以使字符串成为switch语句.实际如何解决问题?

It seems it will not work. Is this possible? I mean is there any way we can make a switch statement of a string. How to solve the problem, actually?

推荐答案

C语言中的switch语句不像其他语言(例如Java 7或Go)中那样聪明，您不能打开字符串(也不能比较) ==的字符串).开关只能在整数类型(int，char等)上操作.

Switch statements in C aren't smart like one's found in other languages (such as Java 7 or Go) you cannot switch on a string (Nor can you compare strings with ==). Switch can only operate on integral types (int, char, etc).

在您的代码中，调用带有switch(name[20])的switch.这意味着switch(*(name + 20)).换句话说，以名称打开第21个char(因为第一个是name[0]).由于name只有20个字符，因此您正在访问名称后的任何内存. (这可能会发生不可预测的事情)

In your code you call switch with: switch(name[20]). That means switch(*(name + 20)). In other words switch on the 21st char in name (because name[0] is the first). As name only has 20 chars you are accessing whatever memory is after name. (which could do unpredictable things)

还将字符串"kevin"编译为包含字符串的char[N](其中N是strlen("kevin") + 1).当您执行case "kevin"时.仅当名称在与存储字符串完全相同的内存中时，它才起作用.因此，即使我将kevin复制到名称中.它仍然不匹配，因为它存储在不同的内存中.

Also the string "kevin" is compiled to a char[N] (where N is strlen("kevin") + 1) which contains the string. When you do case "kevin". It will only work if name is in the exact same piece of memory storing the string. So even if I copied kevin into name. It still would not match as it is stored in a different piece of memory.

要执行您似乎正在尝试的操作，请执行以下操作:

To do what you seem to be trying you would do this:

#include <string.h>
...
    if (strcmp(name, "kevin") == 0) {
        ...
    }

字符串比较(strcmp)根据字符串中的差异返回不同的值.例如:

String compare (strcmp) returns different values based on the difference in the strings. Eg:

int ord = strcmp(str1, str2);
if (ord < 0)  
    printf("str1 is before str2 alphabetically\n");
else if (ord == 0) 
    printf("str1 is the same as str2\n");
else if (ord > 0)  
    printf("str1 is after str2 alphabetically\n");

旁注:请勿以该形式使用scanf("%s", name).它会创建常见的安全问题使用fgets，例如:(有一种安全的使用方法scanf也是

Side note: Dont use scanf("%s", name) in that form. It creates a common security problem use fgets like this: (there is a safe way to use scanf too)

#define MAX_LEN 20
int main() { 
    name[MAX_LEN]; 
    fgets(name, MAX_LEN, stdin);
    ...

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