如何获得两个字符串数组的区别? [英] How to get the difference of two string arrays?

问题描述

我想得到两个字符串数组之间的确切区别.

I want to get the exact difference between two string arrays.

const array1 = ['T','E','A','P','A','P','E','R'];
const array2 = ['T','A','P'];

预期的输出数组:

['E','A','P','E','R']

我尝试过这种方法:

const output = array1.filter(char => array2.includes(char));

但这会删除字符的所有实例，例如:

But that removes all instances of a character, like:

['E','E','R']

我是新手，所以您能指导我正确的方向吗?

I'm a newbie, so could you guide me to the right direction?

推荐答案

您可以关闭第二个数组的索引，并增加索引并将其从结果集中删除.

You could take a closure over the index for the second array and increment the index and remove this item from the result set.

var array1 = ['T', 'E', 'A', 'P', 'A', 'P', 'E', 'R'],
    array2 = ['T', 'A', 'P'],
    result = array1.filter((i => v => array2[i] !== v || !++i)(0));

console.log(result);

没有预定义顺序array2的另一种方法.

A different approach without a predefined order of array2.

var array1 = ['T', 'E', 'A', 'P', 'A', 'P', 'E', 'R'],
    array2 = ['T', 'A', 'P'],
    set2 = new Set(array2)
    result = array1.filter(v => !set2.delete(v));

console.log(result);

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