用fputc在c的整数数组中写入文件 [英] Write a file in c of an array of integers with fputc
问题描述
我正在编写一个程序，该程序读取文件并生成每个字节的整数数组，首先我用.txt文件证明，然后为每个字母及其对应的字节(例如ASCII)生成ASCII因为B是66，而二进制66是01000010，我的程序在.exe窗口中打印出这两个)，但是我需要使用array(rest [x])的整数制作相同的文件，我可以制作一个新文件.txt，但是只有垃圾桶，或者我认为是，file.txt是新文件.txt的名称，并且只有垃圾桶，我想恢复UAM.txt中的文本，并写在数组rest [x]中的file.txt；
I'm writing a program that reads a file and generates an array of integers of each byte, first I prove with a .txt file and I generates the ASCII for each of the letters and its corresping byte(for example the ASCII for B is 66, and the binary of 66 is 01000010, my program print this two in the .exe window), but I need to make the same file with the integers of the array(rest[x]), I could make a new file .txt but it has only trash, or I think is it, file.txt is the name of the new file .txt and it only has trash, I want to recover the text that is in UAM.txt, and writte in file.txt from the array rest[x];
#include<stdio.h>
int main()
{
int b1, b2, b3, b4, b5, b6, b7, b8;
int x, i;
char a, b;
FILE *f1, *bin, *fp;
b1 = 0x01; // = 0000 0001
b2 = 0x02; // = 0000 0010
b3 = 0x04; // = 0000 0100
b4 = 0x08; // = 0000 1000
b5 = 0x10; // = 0001 0000
b6 = 0x20; // = 0010 0000
b7 = 0x40; // = 0100 0000
b8 = 0x80; // = 1000 0000
int mask[8] = { b8, b7, b6, b5, b4, b3, b2, b1 };
int rest[8];
f1 = fopen("UAM.txt", "rb");
fp = fopen("file.txt", "w+");
while (!feof(f1))
{
a = getc(f1);
printf("%d\n", a);
for (i = 0; i <= 7; i++)
{
rest[i] = a & mask[i];
}
for (i = 0; i <= 7; i++)
{
rest[i] = rest[i] / mask[i];
}
for (x = 0; x <= 7; x++)
{
printf("%i", rest[x]);
fputc(rest[x], fp);
}
fclose(fp);
printf("\n");
}
return 0;
}
输入文件可以是任何文本，举个简单的例子，我将B字保存在UAM.txt中，在.exe窗口中，我获得了66和01000010，这是B的ASCII码(十进制和二进制)，接下来是二进制数(即单词的字节)位于整数数组(rest [x])中.我需要再次将该二进制文件转换为字母B，并将该字母或任何文本保存在我名为file.txt的新文件中，此文件中必须再次是字母B或UAM中的任何文本.txt对不起我的英语不好！
the input file can be any text, for a easy example I save the word B in UAM.txt, and in the .exe window I obtained 66 and 01000010 which is the ASCII code for B in decimal and binary, next the binary number which is the byte of the word is located In an integer array(rest[x]). I need to convert this binary again to the letter B, and save this letter or any text in a new file that I named file.txt, in this file has to be again the letter B, or any text that it´s in UAM.txt sorry for my poor english!
任何帮助将不胜感激！
推荐答案
您应该使用mask数组从数组开始重建整数.
You should reconstruct the integer starting from your array using your mask array.
#include<stdio.h>
int main(void)
{
int b1, b2, b3, b4, b5, b6, b7, b8;
int x, i;
char a, b;
FILE *f1, *bin, *fp;
b1 = 0x01; // = 0000 0001
b2 = 0x02; // = 0000 0010
b3 = 0x04; // = 0000 0100
b4 = 0x08; // = 0000 1000
b5 = 0x10; // = 0001 0000
b6 = 0x20; // = 0010 0000
b7 = 0x40; // = 0100 0000
b8 = 0x80; // = 1000 0000
int mask[8] = { b8, b7, b6, b5, b4, b3, b2, b1 };
int rest[8];
f1 = fopen("UAM.txt", "rb");
fp = fopen("file.txt", "w+");
while ((a = fgetc(f1)) != EOF)
{
printf("%d\n", a);
for (i = 0; i <= 7; i++)
{
rest[i] = a & mask[i];
}
for (i = 0; i <= 7; i++)
{
rest[i] = rest[i] / mask[i];
}
a=0;
for (x = 0; x <= 7; x++)
{
printf("%i", rest[x]);
a += rest[x] * mask[x];
}
printf("\n%d\n", a);
fputc(rest[x], fp);
printf("\n");
}
fclose(f1);
fclose(fp);
return 0;
}
更好的方法可能是
#include<stdio.h>
int main(void)
{
int x, i;
char a;
FILE *f1, *fp;
int rest[8];
f1 = fopen("UAM.txt", "rb");
if ( f1 != NULL)
{
fp = fopen("file.txt", "w+");
if ( fp != NULL)
{
while ((a = fgetc(f1)) != EOF)
{
printf("%d\n", a);
for (i = 0; i < 8; i++)
{
rest[i] = a & 0x01;
a>>=1;
}
a=0;
for (x = 7; x >= 0; x--)
{
printf("%i", rest[x]);
a += ((0x01u << x) * rest[x]);
}
fputc(rest[x], fp);
printf("\n");
}
fclose(fp);
}
fclose(f1);
}
return 0;
}
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