c数组:动态设置大小? [英] c arrays: setting size dynamically?

问题描述

我是C编程新手.我正在尝试使用变量设置数组的大小，但出现错误:数组"的存储大小不是恒定的！

I am new to C programming. I am trying to set the size of the array using a variable but I am getting an error: Storage size of 'array' isn't constant !!

01 int bound = bound*4;

02 static GLubyte vertsArray[bound];

我注意到，当我用数字"20"替换 bounds (在第02行的括号内)时，程序可以正常运行.但是我试图动态设置数组的大小...

I have noticed that when I replace bounds (within the brackets on line 02) with the number say '20', the program would run with no problems. But I am trying to set the size of the array dynamically ...

我为什么会收到此错误的任何想法? 非常感谢，

Any ideas why I am getting this error ? thanks much,

推荐答案

您会收到此错误，因为正如编译器告诉您的那样，您的数组大小不是恒定的.在C语言的C89/90版本中，数组大小必须为常数.您不能动态设置数组的大小".如果需要运行时大小的数组，则必须使用malloc手动分配它，或使用某些非标准的编译器特定方法(例如alloca函数).

You are getting this error because, as the compiler told you, your array size is not constant. In C89/90 version of C language array size has to be a constant. You can't "set the size of the array dynamically". If you need a run-time sized array, you have to either allocate it manually with malloc or use some non-standard compiler-specific approach (like alloca function).

在C语言的C99版本中，添加了对所谓的可变长度数组(VLA)的支持. C99编译器将接受自动数组的运行时大小的数组声明.但是，即使在C99中，您也无法像尝试那样声明运行时大小的 static 数组.

In C99 version of C language support for so called Variable-Length Arrays (VLA) was added. A C99 compiler would accept run-time sized array declaration for an automatic array. Yet even in C99 you can't declare a static array of run-time size, as you are trying to.

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