两个Java数组的对称差异 [英] Symmetric difference of two Java arrays

问题描述

我有两个数组

 String[] ID1={"19","20","12","13","14"};

 String[] ID2={"10","11","12","13","15"};  

在比较上面两个数组时，如何获得以下答案.

How can I get following answer while comparing above two arrays.

在比较上面两个数组时，我想排除共同的元素.

I want to exclude common elements while comparing above two arrays.

 String[] Result={"14","15","19","20","10","11"};

推荐答案

似乎您想将两个集合的并集(没有重复项，对吗?)减去交集:

Seems like you want the union of the two sets (no duplicates, right?) minus the intersection:

Set<Integer> union = new HashSet<Integer>(Arrays.asList(ID1));
union.addAll(Arrays.asList(ID2);

Set<Integer> intersection = new HashSet<Integer>(Arrays.asList(ID1));
intersection.retainAll(Arrays.asList(ID2);

union.removeAll(intersection);

// result is left in "union" (which is badly named now)

(我将您的String更改为Integer，这似乎更适合数据，但可以与String一起使用)

(I changed your String to Integer, which seems to fit the data better, but it would work with String the same way)

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