在Fortran中使用序列初始化数组 [英] Initilalising an array with a sequence in Fortran
问题描述
我目前正在翻译一些旧的fortran代码,并且很难理解代码中的特定行.编译器似乎也发现这行很奇怪,并抛出错误.据我了解,它正在尝试通过以1为增量对1到9进行排序来初始化数组,并以列主形式将此序列填充到数组矩阵中.
program arrayProg
integer :: matrix(3,3), i , j !two dimensional real array
matrix = reshape((/1:9:1/), (/3,3/))
end program arrayProg
这种语法在fortran中可以接受吗? (必须是因为它来自旧代码) 我误会了线路的作用吗?
语法不正确,除非实现某些非标准扩展,否则Fortran编译器无法编译此类代码.
英特尔Fortran接受以下条件:
A colon-separated triplet (instead of an implied-DO loop) to specify a range of values and a stride; for example, the following two array constructors are equivalent:
1 INTEGER D(3)
2 D = (/1:5:2/) ! Triplet form - also [1:5:2]
3 D = (/(I, I=1, 5, 2)/) ! implied-DO loop form
来自 https://software.intel.com/en-us/node/678554
要以标准方式生成序列,可以使用隐式的do循环,例如
(/ (i, i=1,9) /)
重塑不仅仅是像您猜到的那样将一维数组按列的主要顺序更改为二维.
I am currently working on translating some legacy fortran code and I am having a hard time understanding a particular line in the code. The compiler also seems to find this line weird and throws out an error. From what I understand it is trying to initialize an array by sequencing 1 to 9 by increments of 1 and filling up the array matrix with this sequence in column major form.
program arrayProg
integer :: matrix(3,3), i , j !two dimensional real array
matrix = reshape((/1:9:1/), (/3,3/))
end program arrayProg
Is this syntax acceptable in fortran? (It has to be because it comes from the legacy code) Am I misunderstanding what the line does?
The syntax is incorrect and such code cannot be compiled by a Fortran compiler, unless it implements some non-standard extension.
Intel Fortran accepts this:
A colon-separated triplet (instead of an implied-DO loop) to specify a range of values and a stride; for example, the following two array constructors are equivalent:
1 INTEGER D(3)
2 D = (/1:5:2/) ! Triplet form - also [1:5:2]
3 D = (/(I, I=1, 5, 2)/) ! implied-DO loop form
from https://software.intel.com/en-us/node/678554
To generate a sequence in a standard way one uses an implied do loop like
(/ (i, i=1,9) /)
the reshape than just changes the 1D array into a 2D one in column major order as you guessed.
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