如何在数字数组中找到前两个连续的元素? [英] How do I find the first two consecutive elements in my array of numbers?

问题描述

例如，使用Ruby 2.4，我有一组唯一的，有序的数字

Using Ruby 2.4, I have an array of unique, ordered numbers, for example

[1, 7, 8, 12, 14, 15]

如何找到前两个元素的差为1?例如，上面的数组的答案是"7"和"8".

How do I find the first two elements whose difference is 1? For example, the above array the answer to that is "7" and "8".

推荐答案

您可以使用each_cons和find从对数组中获取第一个元素，其中第二个元素减去第一个元素等于1:

You could use each_cons and find to get the first element from the array of pairs where the second element less the first one is equal to 1:

p [1, 7, 8, 12, 14, 15].each_cons(2).find { |a, b| b - a == 1 }
# => [7, 8]

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