为什么.forEach返回未定义? [英] Why is .forEach returning undefined?

查看:133
本文介绍了为什么.forEach返回未定义?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我知道此主题已经有多个问题 https://stackoverflow.com/搜索?q =%5Bjavascript%5D + return + forEach +未定义,但是这些似乎都帮不了我.

I know there already are multiple questions to this topic https://stackoverflow.com/search?q=%5Bjavascript%5D+return+forEach+undefined but none of this seemed to help me out.

所以我有以下数据:

 const testsMap = {
            0: ["just", "test"],
            1: ["bla", "asdf"]
        }

 const testArray = [{
    id: "1",
    segments: null,
    tests: [{
            id: "1",
            segments: "1"
        },
        {
            id: "2",
            segments: "0"
        }
    ]
},
{
    id: "2",
    segments: "1",
    tutorials: [{
            id: "1",
            segments: "1"
        },
        {
            id: "2",
            segments: "0"
        }
    ]
}];

我想要使用.map().reduce而不使用输出 来实现的目标是,因为我不想要一个新数组,我只想覆盖现有的数组,如下所示:

What I want to achieve with the output without using .map() or .reduce since I do not want a new array, I just want to overwrite the existing one, is the following:

[{
    display: true,
    id: "1",
    segments: null,
    tests: [{
            display: true,
            id: "1",
            segments: "1",
            newSegments: ["bla", "asdf"]
        },
        {
            display: true,
            id: "2",
            segments: "0",
            newSegments: ["just", "test"]
        }
    ]
},
{
    display: false,
    id: "2",
    segments: "1",
    tutorials: [{
            id: "1",
            segments: "1"
        },
        {
            id: "2",
            segments: "2"
        }
    ]
}];

我拥有的函数看起来像这样-请注意,它具有一些辅助功能fns,您可以忽略该功能-这恰好是fn返回undefined:

The function I have looks something like this - please note that it has some helper fns which you can ignore - it's just about that the fn returns undefined:

function SOtest () {
  const returnedValue = testArray.forEach(test => {
    test.newSegments = test.segments ? testsMap[test.segments] : [];
    test.display = helperFn(); // will add true/false to the test prop

    if (test.display) {
      test.tests.map(t => {
        t.newSegments = t.segments ? testsMap[t.segments] : [];
        t.display = helperFn(); // will add true/false to the test prop
      })
    }
    return test;
  })
  return returnedValue;
}

现在forEach本身在控制台中执行时可以正常工作-但只要我想返回它,它就等于undefined.

Now the forEach itself works just fine when executed by itself in the console - but as soon as I want to return it, it equals undefined.

我想念什么?

推荐答案

forEach不返回任何内容.它只是循环遍历元素,循环时您可以更改元素数据

forEach doesn't return anything. It just loops through elements and while looping you can change element data

因此您可以将功能SOtest更改为

And so you can change your function SOtest to

function SOtest () {
  testArray.forEach(test => {
    test.newSegments = test.segments ? testsMap[test.segments] : [];
    test.display = helperFn(); // will add true/false to the test prop

    if (test.display) {
      test.tests.map(t => {
        t.newSegments = t.segments ? testsMap[t.segments] : [];
        t.display = helperFn(); // will add true/false to the test prop
      })
    }
  })
  return testArray;
}

这篇关于为什么.forEach返回未定义?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆