如何在Java中转换WAV文件 [英] How can I convert a wav file in java

问题描述

如何在Java中转换wav文件

How can I convert a wav file in java

AudioFormat targetFormat = new AudioFormat(
                                    sourceFormat.getEncoding(),
                                    fTargetFrameRate,
                                    16,
                                    sourceFormat.getChannels(),
                                    sourceFormat.getFrameSize(),
                                    fTargetFrameRate,
                                    false);

结果异常:

java.lang.IllegalArgumentException: Unsupported conversion: 
ULAW 8000.0 Hz, **16 bit**, mono, 1 bytes/frame, **from** ULAW 8000.0 Hz, **8 bit**, mono, 1 bytes/frame

在Java中有可能吗?

it is possible in java?

我需要从8获取16位的wav文件

I need get wav file 16 bit, from 8

推荐答案

这里是一种使用内置Java方法将8位uLaw编码的二进制文件转换为16位WAV文件的方法.

Here is a method that will convert an 8-bit uLaw encoded binary file into a 16-bit WAV file using built-in Java methods.

public static void convertULawFileToWav(String filename) {
    File file = new File(filename);
    if (!file.exists())
        return;
    try {
        long fileSize = file.length();
        int frameSize = 160;
        long numFrames = fileSize / frameSize;
        AudioFormat audioFormat = new AudioFormat(Encoding.ULAW, 8000, 8, 1, frameSize, 50, true);
        AudioInputStream audioInputStream = new AudioInputStream(new FileInputStream(file), audioFormat, numFrames);
        AudioSystem.write(audioInputStream, Type.WAVE, new File("C:\\file.wav"));
    } catch (IOException e) {
        e.printStackTrace();
    }
}

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