等待输入时进行Python打印 [英] Python Print while waiting for input

问题描述

def receivedata(self):
    while True:
        data = self.soc.recv(1024)
        if data != "" or data != '' or data != "":
            sys.stdout.write("Recv>> ")
            sys.stdout.write(data)
            sys.stdout.flush()
            if data == "Server Shutdown":
                self.soc.close()
        elif not data:
            continue
def senddata(self):
    while True:
        try:
            sys.stdout.write("Send>> ")
            msg = sys.stdin.readline()
            self.soc.send(msg)
        except socket.error:
            sys.stdout.write("Socket Connection Timed Out")

这是我的python客户端代码的一部分，因此我期望在等待用户输入的同时打印从服务器接收的内容.

This is part of my client code of python, and what I expect from this is while this waits for user input, it prints what it receives from server.

但是，客户端在等待用户输入时不打印任何内容-仅在用户输入内容后才打印.

However, client does not print anything when it is waiting for user input -- it only prints when something has been entered by user.

有没有一种方法可以更改此设置，以便即使在等待用户输入时也可以打印?

Is there a way that I could change this so that it prints even when it is waiting for user input?

推荐答案

如果您的程序需要等待2个单独的事件(用户输入和传入的套接字数据)，则必须使用线程，例如:

If your program needs to wait on 2 separate events (user input and incoming socket data), you'll have to use threads, something like:

recv_thread = threading.Thread(target=receivedata)
recv_thread.setDaemon(True)
recv_thread.start()
senddata()

有关代码的事情:

• 遇到socket.error时，可能不是超时.
• 在某一时刻，您需要从 senddata 中退出while循环(当用户输入特定文本时?)，否则会发生异常.
• 还在 receivedata
中添加异常处理 receivedata 中的

• if语句不正确.您可以将其替换为:

• when socket.error is encountered it can be something other than timeout.
• at one point you will need to exit the while loop from senddata (when the user input a certain text? or) in case of exception.
• also add exception handling in receivedata

• if statement in receivedata is not OK. you could replace it to:

if data:
    ...if statements...

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