使用D3.min查找不为0的最小值 [英] Use D3.min to find lowest value that is not 0

问题描述

我正在尝试使用D3查找数据集中的最低值.但是，我的值也为0，但我希望D3查找不为0的最低值.

I'm trying to use D3 to find the lowest value in my dataset. However, I also have values that are 0, but I want D3 to find the lowest value that is not 0.

当前我正在使用:

d3.min(data，function(d){return d.houseValues;})

d3.min(data, function(d) {return d.houseValues; })

但是很明显，有时在找到0时返回0.

But obviously this returns 0 sometimes, when a 0 is found.

有没有办法做到这一点?还是唯一的构建带有if语句以忽略0值的普通for循环的解决方案??

Is there a way to do this? Or is the only solution to build a normal for-loop with an if-statement to ignore the 0 values..?

谢谢！

推荐答案

您可以使用常量Infinity，因为Math.min(Infinity, someNumber)始终返回someNumber(除非someNumber也是无穷大).所以看起来像这样:

You can use the constant Infinity, since Math.min(Infinity, someNumber) always return someNumber (unless someNumber is also infinity). So it'll look like this:

smallest = d3.min(data, function(d) {return d.houseValues || Infinity; })

如果需要，您可以检查smallest == Infinity，如果所有房屋价值均为0，则为true.

If needed, you can check smallest == Infinity, which would be true in the case that all house values were 0.

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