D3.js-exit()部分不会删除所有数据 [英] D3.js - exit() section does not remove all data
本文介绍了D3.js-exit()部分不会删除所有数据的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我合并了 http://bl.ocks.org/mbostock/950642 和 http://bl.ocks.org/mbostock/1095795 d3将布局示例插入以下代码:
I merged http://bl.ocks.org/mbostock/950642 and http://bl.ocks.org/mbostock/1095795 d3 force layout examples into below code:
<!DOCTYPE html>
<meta charset="utf-8">
<style>
/*.link {
stroke: #000;
stroke-width: 1.5px;
}
.node {
fill: #000;
stroke: #fff;
stroke-width: 1.5px;
}
.node.a { fill: #1f77b4; }
.node.b { fill: #ff7f0e; }
.node.c { fill: #2ca02c; }*/
.link {
stroke: #ccc;
}
.node text {
pointer-events: none;
font: 10px sans-serif;
}
</style>
<body>
<script src="http://d3js.org/d3.v3.min.js"></script>
<script>
var width = 960,
height = 500;
var color = d3.scale.category10();
var nodes = [],
links = [];
var force = d3.layout.force()
.nodes(nodes)
.links(links)
.charge(-400)
.linkDistance(120)
.size([width, height])
.on("tick", tick);
var svg = d3.select("body").append("svg")
.attr("width", width)
.attr("height", height);
var node = svg.selectAll(".node"),
link = svg.selectAll(".link");
// 1. Add three nodes and three links.
setTimeout(function() {
var a = {id: "a"}, b = {id: "b"}, c = {id: "c"};
nodes.push(a, b, c);
links.push({source: a, target: b}, {source: a, target: c}, {source: b, target: c});
start();
}, 0);
// 2. Remove node B and associated links.
setTimeout(function() {
nodes.splice(1, 1); // remove b
links.shift(); // remove a-b
links.pop(); // remove b-c
start();
}, 3000);
// Add node B back.
setTimeout(function() {
var a = nodes[0], b = {id: "b"}, c = nodes[1];
nodes.push(b);
links.push({source: a, target: b}, {source: b, target: c});
start();
}, 6000);
function start() {
link = link.data(force.links(), function(d) { return d.source.id + "-" + d.target.id; });
//link.enter().insert("line", ".node").attr("class", "link");
link.enter().append("line").attr("class", "link");
link.exit().remove();
node = node.data(force.nodes(), function(d) { return d.id;});
node.enter().append("g")
.attr("class", "node")
.call(force.drag);
node.append("image")
.attr("xlink:href", "https://github.com/favicon.ico")
.attr("x", -8)
.attr("y", -8)
.attr("width", 16)
.attr("height", 16);
node.append("text")
.attr("dx", 12)
.attr("dy", ".35em")
.text(function (d) {console.log(d.id); return d.id;});
//node.enter().append("circle").attr("class", function(d) { return "node " + d.id; }).attr("r", 8);
node.exit().remove();
force.start();
}
function tick() {
node.attr("transform", function(d) { return "translate(" + d.x + "," + d.y + ")"; });
link.attr("x1", function(d) { return d.source.x; })
.attr("y1", function(d) { return d.source.y; })
.attr("x2", function(d) { return d.target.x; })
.attr("y2", function(d) { return d.target.y; });
}
</script>
代码执行后，某些svg"g"节点具有多个text和image子节点，不过，正如我支持的那样，应在exit()部分中将其删除.
After code execution some svg "g" nodes have multiple text and image children-nodes, although, as I suppouse, they should be removed in exit() section.
我该如何解决?任何帮助表示赞赏.
How can I fix it? Any help appreciated.
文本和图像节点重复的示例:
Example of text and image nodes duplication:
<g class="node" transform="translate(411.8420674597886,245.93226853324168)">
<image xlink:href="https://github.com/favicon.ico" x="-8" y="-8" width="16" height="16"></image>
<text dx="12" dy=".35em">a</text>
<image xlink:href="https://github.com/favicon.ico" x="-8" y="-8" width="16" height="16"></image>
<text dx="12" dy=".35em">a</text>
<image xlink:href="https://github.com/favicon.ico" x="-8" y="-8" width="16" height="16"></image>
<text dx="12" dy=".35em">a</text>
</g>
Edit2: 正如@LarsKotthoff建议的那样:
As @LarsKotthoff suggested:
<!DOCTYPE html>
<meta charset="utf-8">
<style>
/*.link {
stroke: #000;
stroke-width: 1.5px;
}
.node {
fill: #000;
stroke: #fff;
stroke-width: 1.5px;
}
.node.a { fill: #1f77b4; }
.node.b { fill: #ff7f0e; }
.node.c { fill: #2ca02c; }*/
.link {
stroke: #ccc;
}
.node text {
pointer-events: none;
font: 10px sans-serif;
}
</style>
<body>
<script src="http://d3js.org/d3.v3.min.js"></script>
<script>
var width = 960,
height = 500;
var color = d3.scale.category10();
var nodes = [],
links = [];
var force = d3.layout.force()
.nodes(nodes)
.links(links)
.charge(-400)
.linkDistance(120)
.size([width, height])
.on("tick", tick);
var svg = d3.select("body").append("svg")
.attr("width", width)
.attr("height", height);
var node = svg.selectAll(".node"),
link = svg.selectAll(".link");
// 1. Add three nodes and three links.
setTimeout(function() {
var a = {id: "a"}, b = {id: "b"}, c = {id: "c"};
nodes.push(a, b, c);
links.push({source: a, target: b}, {source: a, target: c}, {source: b, target: c});
start();
}, 0);
// 2. Remove node B and associated links.
setTimeout(function() {
nodes.splice(1, 1); // remove b
links.shift(); // remove a-b
links.pop(); // remove b-c
start();
}, 3000);
// Add node B back.
setTimeout(function() {
var a = nodes[0], b = {id: "b"}, c = nodes[1];
nodes.push(b);
links.push({source: a, target: b}, {source: b, target: c});
start();
}, 6000);
function start() {
link = link.data(force.links(), function(d) { return d.source.id + "-" + d.target.id; });
//link.enter().insert("line", ".node").attr("class", "link");
link.enter().append("line").attr("class", "link");
link.exit().remove();
node = node.data(force.nodes(), function(d) { return d.id;});
var appendedG= node.enter().append("g")
.attr("class", "node")
.call(force.drag);
appendedG.append("image")
.attr("xlink:href", "https://github.com/favicon.ico")
.attr("x", -8)
.attr("y", -8)
.attr("width", 16)
.attr("height", 16);
appendedG.append("text")
.attr("dx", 12)
.attr("dy", ".35em")
.text(function (d) {console.log(d.id); return d.id;});
//node.enter().append("circle").attr("class", function(d) { return "node " + d.id; }).attr("r", 8);
node.exit().remove();
force.start();
}
function tick() {
node.attr("transform", function(d) { return "translate(" + d.x + "," + d.y + ")"; });
link.attr("x1", function(d) { return d.source.x; })
.attr("y1", function(d) { return d.source.y; })
.attr("x2", function(d) { return d.target.x; })
.attr("y2", function(d) { return d.target.y; });
}
</script>
推荐答案
尝试一下:
node = node.data(force.nodes(), function(d) { return d.id;});
var newNode = node.enter().append("g")
.attr("class", "node")
.call(force.drag);
newNode.append("image")
.attr("xlink:href", "https://github.com/favicon.ico")
.attr("x", -8)
.attr("y", -8)
.attr("width", 16)
.attr("height", 16);
newNode.append("text")
.attr("dx", 12)
.attr("dy", ".35em")
.text(function (d) {console.log(d.id); return d.id;});
//node.enter().append("circle").attr("class", function(d) { return "node " + d.id; }).attr("r", 8);
node.exit().remove();
这篇关于D3.js-exit()部分不会删除所有数据的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
查看全文
