快速排序具有多个排序条件的数组 [英] Swift Sort an array with multiple sort criteria
问题描述
在Swift中如何通过多个条件对数组进行排序?例如,如下所示的字典数组:
How is an array sorted by multiple criteria in Swift? For example, an array of dictionaries as shown:
items = [
[
"item":"itemA"
"status":"0"
"category":"B"
],[
"item":"itemB"
"status":"1"
"category":"C"
],[
"item":"itemC"
"status":"0"
"category":"A"
],[
"item":"itemD"
"status":"2"
"category":"A"
]
]
这需要进行如下排序:
- 类别ASC
- 状态DESC
我已经成功地基于 条件1或2对该数组进行了排序,但不是同时基于这两种条件.以下是该代码:
I have successfully sorted this array based on either condition 1 OR 2, but not both. Below is the code for that:
itemArray.sort({
$0["category"] < $1["category"])
})
如何将其扩展为以给定顺序包含多个排序条件?
How can this be expanded to include multiple sort criteria in a given order?
推荐答案
您要进行字典比较,即如果第一个字段相等,则比较第二个字段,否则比较第一个字段.
You want a lexicographic comparison i.e. if the first fields are equal, compare the second fields, otherwise compare the first fields.
由于您不想两次提取数据并且可能会丢失键,因此字典使它变得有些复杂,但这实际上很好,因为==
和<
可以处理可选的比较.
The dictionary complicates it a bit since you don’t want to fetch the data out twice and keys may be missing, but that’s actually fine since ==
and <
can handle optional comparisons.
let result = items.sorted {
switch ($0["category"],$1["category"]) {
// if neither "category" is nil and contents are equal,
case let (lhs,rhs) where lhs == rhs:
// compare "status" (> because DESC order)
return $0["status"] > $1["status"]
// else just compare "category" using <
case let (lhs, rhs):
return lhs < rhs
}
}
实际上在某些情况下可以使用lexicographicCompare
进行比较-但在这种情况下将不起作用,因为a)可选内容虽然可以与<
进行比较,但不符合Comparable
,因此您必须手动检查nil,并且b)您想按降序对第二个条目进行排序.
There’s actually a lexicographicCompare
that you could use under some circumstances to do the comparison – but it won’t work in this case because a) optionals, while they can be compared with <
, don’t conform to Comparable
so you’d have to check for nils manually, and b) you want to sort the second entry in descending order.
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