对星期几文本进行排序 [英] Sort week day texts

问题描述

我将列表["Tue", "Wed", "Mon", "Thu", "Fri"]作为列表，我希望将其作为 ["Mon", "Tue", "Wed", "Thu", "Fri"].

I have list ["Tue", "Wed", "Mon", "Thu", "Fri"] as list, I want to make it as ["Mon", "Tue", "Wed", "Thu", "Fri"].

如何排序?

推荐答案

效率不高，但是如果您有订单的清单，那么他们应该在...

Not very efficient, but if you have a list of the order they're supposed to be in...

>>> m = ["Mon", "Tue", "Wed", "Thu", "Fri"]
>>> n = ["Tue", "Wed", "Mon", "Thu", "Fri", "Tue", "Mon", "Fri"]
>>> sorted(n, key=m.index)
['Mon', 'Mon', 'Tue', 'Tue', 'Wed', 'Thu', 'Fri', 'Fri']

请注意，如果n中存在某个值，而m中没有该值，则会抛出异常.

Note, this will throw an exception if a certain value is present in n that isn't in m.

或将它们放入名称为键且顺序为值的字典中，然后使用key=your_dict.get作为键...类似:

Or put them into a dict with name as key and order as value, then use key=your_dict.get as a key... something like:

>>> d = {name:val for val, name in enumerate(m)}
>>> d
{'Fri': 4, 'Thu': 3, 'Wed': 2, 'Mon': 0, 'Tue': 1}
>>> sorted(n, key=d.get)
['Mon', 'Mon', 'Tue', 'Tue', 'Wed', 'Thu', 'Fri', 'Fri']

这不会引发异常(Py3.x除外，在尝试对None进行排序时会出现错误)，但是您可以使用局部的，明智的方法，在默认值之前或之后进行排序，或者获取list.index的等效行为，请使用key=d.__getitem__或类似的

This won't throw an exception (except on Py3.x where you'll get an error on trying to sort None), but you could use a partial to sensible, sort before or after default, or to get equivalent behaviour of list.index, use key=d.__getitem__ or similar

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