Java排序列表对象按日期升序 [英] Java sort list object by date ascending

问题描述

我想按日期升序按一个参数(日期格式为"YYYY-MM-DD HH:mm")对我的对象列表进行排序.我找不到正确的解决方案.在python中，使用lambda可以很容易地对其进行排序，但是在Java中，它存在问题.

I'd like to sort list of my objects by one argument it's date in format "YYYY-MM-DD HH:mm" by ascending order. I can't find a right solution. In python It's easily to sort it using lambda, but in Java I've a problem with it.

for (Shop car : cars) {
             Collections.sort(cars, new Comparator<Shop>() {
                @Override
                public int compare(final Shop car, final Shop car) {
                    return car.getDate().compareTo(arc.getDate());
            }
        });

提前谢谢！

推荐答案

可以尝试一下.我认为它将起作用:

Can you try that. I think it will work:

SimpleDateFormat f = new SimpleDateFormat("YYYY-MM-DD HH:mm");
        Stream<Date> sorted = l.stream().map(a->{
            try {
                return f.parse(a);
            } catch (ParseException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }
            return null;
        }).sorted();

更新: 以及是否需要列表:

UPDATE: and if you want a list:

List sorted = l.stream().map(a->{
            try {
                return f.parse(a);
            } catch (ParseException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }
            return null;
        }).sorted().collect(Collectors.toList());

已更新:(使用汽车"进行更新的问题)

UPDATED: (as question updated using "cars")

SimpleDateFormat f = new SimpleDateFormat("YYYY-MM-DD HH:mm");
        List<Car> sorted = cars.stream().sorted(
                (a,b)->
        {
            try {
                return f.parse(a.getDate()).compareTo(f.parse(b.getDate()));
            } catch (ParseException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }
            return 0;
        }
        ).collect(Collectors.toList());

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