如何对时间戳列表进行排序? [英] How to sort timestamp list?

问题描述

我有一个timestamp(long)列表，其中我必须根据时间或添加的列表对列表进行排序.

I have a list of timestamp(long) in which I have to sort list base on time or list added.

我已经尝试并搜索了，但是现在可以正常工作了.

I have tried and searched but its now working.

 Collections.sort(vehicles, new Comparator<VehicleListModel.Vehicle>() {
                @Override
                public int compare(VehicleListModel.Vehicle o1, VehicleListModel.Vehicle o2) {
                    try {
                        DateFormat format = new SimpleDateFormat("MM-dd-yyyy hh:mm:ss");
                        return format.parse(o1.getCreated()).compareTo(format.parse(o2.getCreated()));
                    } catch (Exception e) {
                        e.printStackTrace();
                        return 0;
                    }
                }
            });
            customerListAdapter.notifyDataSetChanged();

它不起作用，然后我尝试了 此，但此Date(timeStamp)已弃用

its not working then I tried this but this Date(timeStamp) is deprecated

请帮助

推荐答案

如果getCreated返回Date，则可以使用compareTo比较两个日期，并根据此比较对列表进行排序，例如:

If getCreated returns a Date then you can compare two dates using compareTo and sort the list based on this comparison, e.g.:

List<VehicleListModel.Vehicle> list = new ArrayList<>();
list.sort((e1, e2) -> e1.getCreated().compareTo(e2.getCreated()));

更新

如果getCreated返回long值，则可以将其装箱并使用Long类的compareTo方法，例如:

If getCreated returns long value then you can box it and use compareTo method of Long class, e.g.:

List<ChainCode> list = new ArrayList<ChainCode>();
list.sort((e1, e2) -> new Long(e1.getCreated()).compareTo(new Long(e2.getCreated())));

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